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2 years ago

Which of the following represents the expression 3 3 3 3 5 5 5 5 5 5

Mathematics

1 answer:

Mice21 [21]2 years ago

6 0

Answer:

Msjusjsudjdudududusuhdu

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Which 2-digit number is equal to the sum of its first digit plus the square of its second digit?

LenaWriter [7]

Let, the two-digit number = xy

It is given that, xy = x + y²

Then, number which obey the rule is 89.

Check: 8 + 9² = 8 + 81 = 89 [ Itself ]

In short, Your Answer would be: 89

Hope this helps!

8 0

3 years ago

i haven't submitted a single assignment for this class since winter break bc i didn't realize she was assigning things on goform

rosijanka [135]

Answer and Step-by-step explanation:

<u>Trigonometric Function (These only work for right triangles):</u>

SOH-CAH-TOA

S = Sine = sin

C = Cosine = cos

T = Tangent = tan

O = Opposite (side)

H = Hypotenuse (side)

A = Adjacent (side)

SOH = sin(angle) = $\frac{opposite}{hypotenuse}$

CAH = cos(angle) = $\frac{adjacent}{hypotenuse}$

TOA = tan(angle) = $\frac{opposite}{adjacent}$

1. sinQ (Q is the angle) = $\frac{14}{50} = \frac{7}{25} = 0.28$

Use Pythagorean Theorem to find side PQ. $14^{2} + PQ^{2}= 50^{2} \\PQ^{2} = 2304\\PQ = 48$

2. cosQ = $\frac{48}{50} = \frac{24}{25} = 0.96$

3. tanQ = $\frac{14}{48} = \frac{7}{24} = 0.29$

3 0

3 years ago

Find the median of the set of data this box-and-whisker plot represents.

egoroff_w [7]

Answer:

18 I think

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

7. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point) f(g(x)) = 2 Square root of quantity two

AlladinOne [14]

Answer:

f(g(x)) =

$\sqrt{8x \: - \: 13} \: + \: 9$

Step-by-step explanation:

f(x) =

$\sqrt{x} \: + \: 9$

g(x) = 8x - 13

f(g(x) =

$\sqrt{8x \: - 13} \: + \: 9$

5 0

3 years ago

Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4

Alik [6]

Answer:

$\alpha=3$

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

$(x-h)^2+(y-k)^2=r^2$

We are given the equation of a circle as

$3x^2+3y^2-6\alpha x+12y-3\alpha=0$

Note we have corrected it by adding the square to the y. Simplify by 3

$x^2+y^2-2\alpha x+4y-\alpha=0$

Complete squares and rearrange:

$x^2-2\alpha x+y^2+4y=\alpha$

$x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4$

$(x-\alpha)^2+(y+2)^2=r^2$

We can see that, if r=4, then

$\alpha+\alpha^2+4=16$

Or, equivalently

$\alpha^2+\alpha-12=0$

There are two solutions for $\alpha$ :

$\alpha=-4,\ \alpha=3$

Keeping the positive solution, as required:

$\boxed{\alpha=3}$

8 0

3 years ago