What is asked in the problem is simply the volume of the solid rubber ball. The volume of sphere given the diameter may be calculated by,
V = πd^3 / 6
Substituting the given value of diameter,
V = (π x 3³) / 6 = 9π/2 or 14.14
Thus, one needs approximately 14.14 in³ of material.
You can't use more then 500
Refer to the diagram shown below.
BE = 2x² - x
DE = x² + 6
The intersecting diagonals bisect one another.
Therefore BE = DE, so that
2x² - x = x² + 6
x² - x - 6 = 0
Factorize.
(x + 2)(x - 3) = 0
x = -2, or x = 3.
When x = -2,
BE = 2(-2)² - (-2) = 10
DE = (-2)² + 6 = 10
Therefore BD = 20
When x = 3;
BE = 2(3²) - 3 = 15
DE = 3² + 6 = 15
Therefore BD = 30
Answer: Either 20 or 30.
First, assign two variables to the prices of the two appliances.
'w' will represent the price of a washer, and 'd' will represent the price of a dryer.
Because "the washer is three times the cost of the dryer," we can form this equation:
w = 3d
On top of that, we know the washer and dryer add up to 600, making another equation.
w + d = 600
Because we know the value of 'w,' we can input that into the equation 'w + d = 600'
(3d) + d = 600
Simplify:
4d = 600
d = 150
Since the washer is three times the price of the dryer:
w = 3(150) = 450
The dryer costs $150, and the washer costs $450.
-T.B.
Answer:
35%
Step-by-step explanation:
To figure out the percentage of bronze medals, we must figure out the percentages of the gold and silver medals first.
We already know that 45% of the medals were silver.
We know that 4 of the 20 medals were gold.
4/20 as a percentage would be 20/100, or 20%.
So, 20% of the medals were gold, and 45% of them were silver.
45% + 20% = 65%
100% - 65% = 35%
So, 35% of the medals awarded were bronze.
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