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3 years ago

Nolan divides his 82 toy cars into boxes. Each box holds 9 cars. How many boxes does Nolan need to store all of his cars?

Mathematics

2 answers:

gregori [183]3 years ago

6 0

Nolan needs 10 boxes

gulaghasi [49]3 years ago

4 0

Answer:

10 boxes/ 9 boxes with 9 cars and 1 box with 1 car

Step-by-step explanation:

if he has 82 cars and whats to put them in boxes and 9 cars fit in each box you need to divide 82/9

82/9=9.1

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What are my like terms here: <br><br> 4b, b, 7, 9b

netineya [11]

Answer:

4b, b, and 9b are like terms

Step-by-step explanation:

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3 years ago

Carissa earns $450 per week for a 40 hour work week plus $16.83 per hour for each hour of overtime after 40 hours. Write an equa

gavmur [86]

Answer:

W = 450 + 16.83V

Step-by-step explanation:

For 40 hours Carissa

earning = $450

earning for 1 hour of over time = $16.83

multiplying both side by V

earning for v hour of over time = $16.83*V = $16.83V

weekly wage(W) = earning for 40 hours + earning for V hour of over time

W = 450 + 16.83V

Thus equation will be as given below for weekly earning

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3 years ago

Can i please have help ill give brainlist (pic below)

Marina CMI [18]

Answer:

Step-by-step explanation:

Because we are reflecting across the X-axis, the X coordinate does not change. On the other hand, the Y coordinate becomes its opposite. So we get:

(2, 4) -> (2, -4)

8 0

2 years ago

Read 2 more answers

A triangle is 10 ft tall and 18 ft wide what is the area of the triangle

erica [24]

The answer is 90 feet

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3 years ago

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Let II be the tangent plane to the graph of f(x, y) = 8 – 2x^2 – 3y^2 at the point (1, 2,-6). Let S, x² + y^2 + z = 4 be another

stealth61 [152]

Let $F(x,y,z)=f(x,y)-z$ . The tangent plane to $f(x,y)$ at (1, 2, -6) has equation

$\nabla F(1,2,-6)\cdot(x-1,y-2,z+6)=0$

We have

$\nabla F(x,y,z)=(-4x,-6y,-1)\implies\nabla F(1,2,-6)=(-4,-12,-1)$

Then the tangent plane has equation

$(-4,-12,-1)\cdot(x-1,y-2,z+6)=0\implies -4(x-1)-12(y-2)-(z+6)=0\implies 4x+12y+z=22$

Let $g(x,y)=4-x^2-y^2$ , and $G(x,y,z)=g(x,y)-z$ . The tangent plane to $S$ at a point $(a,b,c)$ is

$\nabla G(a,b,c)\cdot(x-a,y-b,z-c)=0$

We have

$\nabla G(x,y,z)=(-2x,-2y,-1)\implies \nabla G(a,b,c)=(-2a,-2b,-1)$

so that this plane has equation

$(-2a,-2b,-1)\cdot(x-a,y-b,z-c)=0\implies2ax+2by+z=2a^2+2b^2+c$

In order for this plane to be parallel to the previous plane, we need to have

$\begin{cases}2a=4\\2b=12\end{cases}\implies a=2,b=6\implies g(a,b)=c=-36$

so the point we're looking for is (2, 6, -36).

6 0

3 years ago