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Misha Larkins [42]
3 years ago
14

The measures of the two equal angles of an isosceles triangle are 370 each, then the

Mathematics
1 answer:
e-lub [12.9K]3 years ago
5 0

Answer:

something is incorrect in your question.

Step-by-step explanation:

The sum of all three angles in any triangle is only 180°.

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2. A vanilla milkshake recipe calls for 3/8 cups of vanilla ice cream for every 1/3 cups of milk. How many cups of vanilla ice c
Triss [41]

Answer:

1 1/8 cups of vanilla for a cup of milk.

Step-by-step explanation:

v-3/8  m-1/3

v-6/8  m-2/3

v-1 1/8 m-1

3 0
3 years ago
2296.0 m= ____________ km in metric conversions
Andreyy89

Answer:

2.296 km

Step-by-step explanation:

The "meters to kilometers" conversion factor is:

 1 km

-------------

1000 m

Multiply 2296.0 m by this factor:

 1 km           2296.0 m

------------- * ------------------- = 2.296 km

1000 m               1

3 0
4 years ago
Read 2 more answers
Plz help me and plz show work
Flauer [41]

Answer:

21. The slope is 50.

22. 0

23. y=50x

24. $2600

Step-by-step explanation:

21. The slope of the line is 50. Slope is defined as "rise over run". As the line increases, each segment moves up the y-axis by $50, and to the right on the x-axis 1 segment. (Work: 50 divided by 1)

22. The y-intercept is (0, 0), or simply 0. If you look at the graph you can see that the line crosses the y-axis at the origin. This makes the y-intercept equal to 0.

23. The slope tells you that the student makes $50 every week. The y-intercept is 0. Using the formula y=mx+b, an appropriate equation would be y=50x.

24. The equation found in problem 23 can me used to determine how much a student makes (y) after "x" weeks. Substitute 52 for x to solve for y. This becomes y=50(52). This can be simplified to y=2600. This means that after 52 weeks, the student will have made $2,600.

8 0
3 years ago
Read 2 more answers
What is the surface area of the right prism given below?
posledela

Answer: Option D.

Step-by-step explanation:

You can calculate the surface area of this right prism by adding the area of its faces.

You can observe that the faces of the right prism are:  Three different rectangles and two equal triangles.

The formula for calculate the  area of a rectangle is:

A=lw

 Where "l" is the lenght and "w" is the width.

The formula for calculate the  area of a triangle is:

A=\frac{bh}{2}

Where "b" is the base and "h" is the height.

You can observe that the hypotenuse of the each triangle is the width of one of the larger rectangle, then , you can find its value with the Pythagorean Theorem:

a=\sqrt{b^2+c^2}

Where "a" is the hypotenuse and "b" and "c" are the legs of the triangle.

Then, this is:

a=\sqrt{(8units)^2+(15units)^2}=17units

Therefore, you can add the areas of the faces to find the surface area of the right prism (Since the triangles are equal, you can multiply the area of one of them by 2). This is:

SA=(10units)(8units)+(15units)(10units)+(17units)(10units)+2(\frac{(15units)(8units)}{2})\\\\SA=520units^2

5 0
3 years ago
Read 2 more answers
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
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