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damaskus [11]
2 years ago
14

Does anyone know what is -17+8y=2x?

Mathematics
1 answer:
ANTONII [103]2 years ago
4 0
Answer: 2x-8y=-17

Hope this helps :p
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a rectangular tabletop has a length of 4 3/4 feet and an area fo 11 7/8 square feet. What is the width of the tabletop?
GenaCL600 [577]
W=A/L; 11 7/8 ÷ 3/34= 3 1/6ft
5 0
3 years ago
I need help for solving 4.8(x+4)=2.16
Bas_tet [7]
I hope this helps you



4,8 (x+4)=2,16



48 (x+4)=21,6


x+4=21,6/48


x+4= 0,45


x=0,45-4


x= -3,55


5 0
3 years ago
Read 2 more answers
Rewrite this expression using a positive exponent.<br> -7<br> 5
Sergio [31]

Answer:

1/5^7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Enter your answer and show all the steps that you use to solve this problem.
slamgirl [31]

Answer:

h = -t+20

After 8 hours the candle will be 12 inches

Step-by-step explanation:

We have 2 points (time, inches)

 (3,17)  and (5,15)

We can find the slope

m = (y2-y1)/(x2-x1)

   = (15-17)/(5-3)

   = -2/2

   = -1

We can use point slope form

y-y1 = m(x-x1)

Replace y with h and x with t

h-17 = -1 (t-3)

Distribute

h-17 = -t+3

Add 17 to each side

h-17+17 = -t+3+17

h = -t+20

3 0
3 years ago
Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.
blagie [28]
A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\&#10;5x-4=-2 \times 3x-2 \times 2 \\&#10;5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\&#10;11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\&#10;11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\&#10;x=0

B.
3(2x-4)=5x-1 \\&#10;6x-12=5x-1 \\&#10;\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\&#10;11x=11 \\&#10;\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\&#10;3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\&#10;x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\&#10;x=11
3 0
2 years ago
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