All categories

3 years ago

Help please !!!!!!!!

Mathematics

1 answer:

AlekseyPX3 years ago

5 0

Answer:

Place the left of the dot on -5 and the right one on +7

That should do it :)

You might be interested in

J'ai un exercice de maths pour demain merci de commenter au plus vite

kari74 [83]

Oui je peux the aider

8 0

3 years ago

Which of the following is a characteristic of the circumcenter of a triangle? A. It is the center of the circle that can be insc

ki77a [65]

Answer is A. It is the center of the circle that can be inscribed in a given triangle
Explanation
The circumcenter is called ”the circumcenter” because it is the center of the circle that ”circumscribes” the triangle.

6 0

2 years ago

ABF = EDG. GCF are equilateral. AG = 21 and CG 1/4 Find the total distance from A to B to C to D to E.

hjlf

The information given in the triangle shows that the total distance from A to B to C to D to E will be C. 84.

<h3>How to calculate the triangle?</h3>

From the information given, ABF = EDG, GCF are equilateral and AG = 21 while CG = 1/4.

The total distance from A to B to C to D to E will be:

= 21/CG

= 21 / 1/4

= 21/0.25

= 84

In conclusion, the correct option is 84.

Learn more about triangles on:

brainly.com/question/17335144

3 0

2 years ago

What's 0.875 as a fraction in simplest form

zhenek [66]

$0.875=\dfrac{875}{1000}=\dfrac{875:25}{1000:25}=\dfrac{35:5}{40:5}=\boxed{\frac{7}{8}}$

8 0

3 years ago

Solve the following pair of equations simultaneously.

Alchen [17]

Answer:

No solutions.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination
Solving systems of equations by graphing
Expanding
Finding roots of a quadratic
Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define systems

2x - y = 9

4x² + 3y² - 2x + y = 16

Step 2: Rewrite systems

2x - y = 9

Subtract 2x on both sides: -y = 9 - 2x
Divide -1 on both sides: y = 2x - 9

Step 3: Redefine systems

y = 2x - 9

4x² + 3y² - 2x + y = 16

Step 4: Solve for x

Substitution

Substitute in y: 4x² + 3(2x - 9)² - 2x + (2x - 9) = 16
Expand: 4x² + 3(4x² - 36x + 81) - 2x + (2x - 9) = 16
Distribute 3: 4x² + 12x² - 108x + 243 - 2x + 2x - 9 = 16
Combine like terms: 16x² - 108x + 234 = 16
Factor GCF: 2(8x² - 54x + 117) = 16
Divide 2 on both sides: 8x² - 54x + 117 = 8
Subtract 8 on both sides: 8x² - 54x + 109 = 0
Define variables: a = 8, b = -54, c = 109
Resubstitute: $x=\frac{54\pm\sqrt{(-54)^2-4(8)(109)} }{2(8)}$
Exponents: $x=\frac{54\pm\sqrt{2916-4(8)(109)} }{2(8)}$
Multiply: $x=\frac{54\pm\sqrt{2916-3488} }{16}$
Subtract: $x=\frac{54\pm\sqrt{-572} }{16}$

Here we see that we start to delve into imaginary roots. Since on a real number plane, we do not have imaginary roots, there would be no solution to the systems of equations.

Step 5: Graph systems

We can verify our results.

8 0

3 years ago