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siniylev [52]
3 years ago
7

Sheila either walks or cycles to school. The probability that she walks is 0.65, is she walks the probability she is late is 0.4

. If she cycles the probability that she is late is 0.1. Work out the probability that on any one day Sheila will not be late for school
Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

0.705

Step-by-step explanation:

From the question :

P(not being late) = p(walking and not late) + P(cycling and not late)

P(walking and not being late) = 0.65 * (1 - 0.4) = 0.65 * 0.6 = 0.39

P(cycling and not being late ) = (1 - 0.65) * (1 - 0.1) = 0.35 * 0.9 = 0.315

Hence,

P(not being late) = 0.39 + 0.315 = 0.705

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Step-by-step explanation:

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\displaystyle y > x + 2 \\ \\ 0 ≯ 2[We shade the part of the graph that does not contain the origin, which is the left side.]

So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], therefore the bottom left graph matches what we want.

** By the way, you meant \displaystyle y > x + 2because this inequality in each graph is a <em>dashed</em><em> </em><em>line</em>. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.

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Answer:

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Why is the accounting cycle important?
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Because without it the economy would fail :)
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Step 1: Choose ONE of the following triangles and complete the table below:
Archy [21]

The question is incomplete below you will find the missing part.

Step 1 : Choose ONE of the following triangles complete the table below:

1. Obtuse Scalene Triangle Translation to prove SSS Congruence

or

2. Isosceles Right Triangle Reflection to prove ASA Congruence

or

3. Equilateral Equiangular Triangle Rotation to prove SAS Congruence

Original Coordinate Point

Transformation Rule

Image Coordinate Points

A (1, 4)      (x,y) -> (x+ ,y -)      A’ ( , )

B ( 7,4)     (x,y) -> (x+ ,y - )     B’ ( , )

C (8,9)      (x,y) -> (x+ ,y -)     C’ ( , )

The appropriate table is also shown below.

The triangles ABC and A'B'C' are congruent by SSS through Obtuse Scalene Triangle Translation  because the corresponding sides are congruent

Two triangles are congruent if their size and shape are the same.

Now we have to transform the triangle,

The coordinates of the triangle ΔABC are given as:

A = (1, 4)

B = (7,4)

C = (8,9)

so the lengths of the sides of the triangle are given by

AB= √(7-1)²+(4-4)²= √6²= 6

BC= √(8-7)²+(9-4)²= √1²+5²= √1+25= √26

CA= √(8-1)²+(9-4)²= √7²+5²= √49+25= √74

In order to prove the SSS congruence, we have to transform the triangles under the following translation rule:

(x,y) -> (x -3, y +6)

in the above translation,

The triangle will be translated 3 units left

And then translated 6 units up.

So, we have the new coordination of the points of the translated triangle ΔA'B'C'

A' = (1-3, 4+6)

A' = (-2, 10)

B' = (7-3, 4+6)

B' = (4, 10)

C' = (8-3, 9+6)

C' = (5, 15)

Now

so the lengths of the sides of the triangle are given by

A'B'= √(4-(-2))²+(10-10)²= √6²= 6

B'C'= √(5-4)²+(15-10)²= √1²+5²= √1+25= √26

C'A'= √(-2-5)²+(10-15)²= √(-7)²+(-5)²= √49+25= √74

By comparing two triangles ΔABC and ΔA'B'C'

AB ≅ A'B'

BC ≅ B'C'

CA ≅ C'A'

Hence ΔABC ≅ A'B'C' (By S-S-S rule)

By the above transformation, the triangles ABC and A'B'C' are congruent by SSS because the corresponding sides are congruent as all the points are gone through the same transformation.

Learn more about the transformation

here: brainly.com/question/4289712

#SPJ10

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Answer:

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Step-by-step explanation:

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