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siniylev [52]
3 years ago
7

Sheila either walks or cycles to school. The probability that she walks is 0.65, is she walks the probability she is late is 0.4

. If she cycles the probability that she is late is 0.1. Work out the probability that on any one day Sheila will not be late for school
Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

0.705

Step-by-step explanation:

From the question :

P(not being late) = p(walking and not late) + P(cycling and not late)

P(walking and not being late) = 0.65 * (1 - 0.4) = 0.65 * 0.6 = 0.39

P(cycling and not being late ) = (1 - 0.65) * (1 - 0.1) = 0.35 * 0.9 = 0.315

Hence,

P(not being late) = 0.39 + 0.315 = 0.705

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3 years ago
Jane draws a line in the coordinate plane that passes through the points (2,3) and (6,9)
timofeeve [1]

Answer:

y=x+1

Step-by-step explanation:

To find the line of the equation, use the slope formula to find the slope.

Slope formula is: y2-y1/x2-x1

9-3/6-2= 3/4

Once you have the slope, use that and one of the coordinates to put the equation in point-slope form.

Point-slope form is: y-y1=m(x-x1), with m representing slope and y1 and x1 representing the x and y coordinates.

y-3=1(x-2)

With the equation in point-slope form, you can now distribute 1 to x-2 and simplify to put it in slope-intercept form.

y-3=1x-2

y=x+1

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3 years ago
Read 2 more answers
20 points! I would really like some help! :) (Question attached below)
snow_lady [41]

Answer:

See below.

Step-by-step explanation:

(a)

To multiply two polynomials, multiply every term of the first polynomial by every term of the second polynomial. Then combine like terms.

(\dfrac{1}{2}x - \dfrac{1}{4})(5x^2 - 2x + 6) =

= \dfrac{1}{2}x \times 5x^2 - \dfrac{1}{2}x \times 2x + \dfrac{1}{2}x \times 6 - \dfrac{1}{4} \times 5x^2 + \dfrac{1}{4} \times 2x - \dfrac{1}{4} \times 6

= \dfrac{5}{2}x^3 - x^2 + 3x - \dfrac{5}{4}x^2 + \dfrac{1}{2}x - \dfrac{3}{2}

= \dfrac{5}{2}x^3 - \dfrac{9}{4}x^2 + \dfrac{7}{2}x - \dfrac{3}{2}

(b)

No. Since the binomials are different, the product of two different binomials and the same trinomial will give different results.

4 0
3 years ago
How do I find the equation of the perpendicular bisector between (-2,5) and (2,-1)?
Arturiano [62]

Answer:

y =  \frac{2}{3} x + 2

Step-by-step explanation:

Start by finding the slope of the given line.

\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }

Slope of given line

=  \frac{5 - ( - 1)}{ - 2 - 2}

=  \frac{5 + 1}{ - 4}

=  \frac{6}{ - 4}

=  -  \frac{3}{2}

A perpendicular bisector cuts through the line at its midpoint perpendicularly.

The product of the slopes of two perpendicular lines is -1.

Let the slope of the perpendicular bisector be m.

-  \frac{3}{2} m =  - 1

m =  - 1 \div ( -  \frac{3}{2} )

m =  - 1 \times ( -  \frac{2}{3} )

m =  \frac{2}{3}

y =  \frac{2}{3}x  + c, where c is the y-intercept.

To find the value of c, we need to substitute a pair of coordinates that lies on the perpendicular bisector into the equation. Since the perpendicular bisector passes through the midpoint of the given line, we can use the midpoint formula to find the coordinates.

\boxed{midpoint = ( \frac{x _{1} + x _2}{2} , \frac{y_1  + y_2}{2} )}

Midpoint of given line

=  ( \frac{ - 2+ 2}{2} , \frac{5 - 1}{2} )

=( \frac{0}{2} , \frac{4}{2} )

= (0, 2)

y =  \frac{2}{3} x + c

When x= 0, y= 2,

2= ⅔(0) +c

2= 0 +c

c= 2

Thus, the equation of the perpendicular bisector is y =  \frac{2}{3} x + 2.

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Answer:

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Step-by-step explanation:

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