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denis-greek [22]
2 years ago
7

Suppose that when you ride on your 7.50 kg bike the weight of you and the bike is supported equally by the two tires. If the gau

ge pressure in the tires is 65.5 lb/in^2 and the area of contact between each tire and the road is 7.03 cm^2. What is your weight?W=____ N
Physics
1 answer:
natali 33 [55]2 years ago
4 0

Answer: 567 N

Explanation:

If the weight of the person and the bike are supported equally by the two tires, this means that the force acting on each tire, is half of the total weight.

We know that the gauge pressure in one tire, by definition, is equal to the force on the tire, over the contact surface between each tire and the road, so we can write:

P= F/A = (mrider g + mbike g) / A = (Fgrider + 7.5 kg. 9.8 m/s2) / 703 mm2 (1)

As the pressure data is given in lb/in2, it is needed to convert to N/mm2, as follows:

65.5 lb/in2 = 0.455 N/mm2.

Replacing in (1), and solving for  Fgrider, we have:

Fgrider = 567 N

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The current flowing in each resistor of the circuit is 4 A.

<h3>Equivalent resistance of the series resistors</h3>

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Particle A of charge 2.79 10-4 C is at the origin, particle B of charge -5.64 10-4 C is at (4.00 m, 0), and particle C of charge
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Answer:

a) 0 b) 29.9 N c) 21.7 N d) -17.4 N e) -13.0 N f) -17.4 N  g) 16.9 N

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a) As the electric force is exerted along the line that joins the charges, due to any of the charges A or C has non-zero x-coordinates, the force has no x components either.

So, Fcax = 0

b) Similarly, as Fx = 0, the entire force is directed along the y-axis, and is going upward, due both charges repel each other.

Fyca = k*qa*qc / rac² = (9.10⁹ N*m²/C²*(2.79)*(1.07)*10⁻⁸ C²) / 9.00 m²

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⇒ Fbc = k*qb*qc / rbc² = (9.10⁹ N*m²/C²*(5.64)*(1.07)*10⁻⁸ C²) / 25.0 m²

⇒ Fbc = 21.7 N

d) In order to get the x component of Fbc, we need to get the projection of Fcb over the x axis, taking into account that the force on particle C is attractive, as follows:

Fbcₓ = Fbc * cos (-θ) where θ, is the angle that makes the line of action of the force, with the x-axis, so we can write:

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Fcby = Fcb* sin (-θ) = 21.7* (-3.00/5.00) = -13.0 N

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Fcy = 29.9 N + (-13.0 N) = 16.9 N

h) The magnitude of the resultant electric force acting on C, can be found just applying Pythagorean Theorem, as follows:

Fc = √(Fcx)²+(Fcy)² = (17.4)² + (16.9)²\sqrt{((17.4)^{2} +(16.9)^{2}} = 24.3 N

The angle from the horizontal can be found as follows:

Ф = arc tg (16.9 / 17.4) = 44.2º

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