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denis-greek [22]
3 years ago
7

Suppose that when you ride on your 7.50 kg bike the weight of you and the bike is supported equally by the two tires. If the gau

ge pressure in the tires is 65.5 lb/in^2 and the area of contact between each tire and the road is 7.03 cm^2. What is your weight?W=____ N
Physics
1 answer:
natali 33 [55]3 years ago
4 0

Answer: 567 N

Explanation:

If the weight of the person and the bike are supported equally by the two tires, this means that the force acting on each tire, is half of the total weight.

We know that the gauge pressure in one tire, by definition, is equal to the force on the tire, over the contact surface between each tire and the road, so we can write:

P= F/A = (mrider g + mbike g) / A = (Fgrider + 7.5 kg. 9.8 m/s2) / 703 mm2 (1)

As the pressure data is given in lb/in2, it is needed to convert to N/mm2, as follows:

65.5 lb/in2 = 0.455 N/mm2.

Replacing in (1), and solving for  Fgrider, we have:

Fgrider = 567 N

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An iron wire has a length of 1.50 m and a cross sectional area of 0.290 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and
lapo4ka [179]

Answer:

1.35 A

Explanation:

Applying,

V = IR

I = V/R..................... Equation 1

I = Current, V = Voltage, R = Resistance.

But,

R = Lρ/A............... Equation 2

Where L = Length of the wire, ρ = resistivity, A = Cross-sectional area of the wire.

Sustitute equation 2 into equation 1

V = AV/Lρ............... Equation 3

From the question,

Given: V = 0.7 V, A = 0.290 mm² = 2.9×10⁻⁷ m², L = 1.5 m, ρ = 10×10⁻⁸ Ω.m

Substitute these values into equation 3

I = (0.7× 2.9×10⁻⁷)/(1.5× 10×10⁻⁸ )

I = (2.03×10⁻⁷)/(15×10⁻⁸)

I = 1.35 A

5 0
3 years ago
What is the electrical force between q2 and q3? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 1. 0 × 1011
nlexa [21]

Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

<h3>What is electric force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

\rm F= K\frac{q_2q_3}{r^2}

\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}

\rm F=  - 1. 1 \times 10^{11 }N

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

brainly.com/question/1076352

4 0
3 years ago
When comparing two circuits, you note that circuit one has twice the resistance and double the voltage of circuit two. This mean
pochemuha

This means that there is same current flow in both the circuit, or the circuit one has twice the power of circuit two.

According to ohm's law, the resistance is given as

I=V/R

Since the circuit one has twice the voltage, and resistance

I1=I2

5 0
3 years ago
Read 2 more answers
A leaf is floating on the Surface of the water,what will happen to its movement? Explain
docker41 [41]

Answer:

MRCORRECT has answered the question

Explanation:

surface tension of water helps creatures(mostly of insecta class such as water striders) to walk on water. . it also helps water to move up the xylem tissue ofhigher plants without breaking up

4 0
3 years ago
An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
mel-nik [20]

Answer:

Explanation:

All the displacement will be converted into vector, considering east as x axis and north as y axis.

5.3 km north

D = 5.3 j

8.3 km at 50 degree north of east

D₁= 8.3 cos 50 i + 8.3 sin 50 j.

= 5.33 i + 6.36 j

Let D₂ be the displacement which when added to D₁ gives the required displacement D

D₁ + D₂ = D

5.33 i + 6.36 j + D₂ = 5.3 j

D₂ = 5.3 j - 5.33i - 6.36j

= - 5.33i - 1.06 j

magnitude of D₂

D₂²= 5.33² + 1.06²

D₂ = 5.43 km

Angle θ

Tanθ = 1.06 / 5.33

= 0.1988

θ =11.25 ° south of due west.

4 0
3 years ago
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