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yanalaym [24]
3 years ago
11

Complete the table of values for the equation 2y +6x =6

Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

85

Step-by-step explanation:

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Is my work correct here I'm supposed to find the first four terms using the recursion formula?
inessss [21]

Answer:

<u>yes your formula is correct </u>

Step-by-step explanation:

5 0
3 years ago
Find the prime factorization of 196. Use a method of your choice. List your final answer
hammer [34]
Positive Integer factors of 196 = 2, 4, 7, 28, 196 divided by 2, 2, 7, 7, gives no remainder. If we put all of it together we have the factors 2 x 2 x 7 x 7 = 196. It can also be written in exponential form as 22 x 72.

(I got all of this from google so i hope it’s right!)
3 0
3 years ago
1. Solve -y/12 = 6<br> 2. Solve x/4 = 8
OlgaM077 [116]

1. Isolate the y. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

First, multiply 12 to both sides

-y/12(12) = 6(12)

-y = 6(12)

-y = 72

Isolate the y. Divide -1 from both sides

-y/-1 = 72/-1

y = -72

-72 is your answer for y

--------------------------------------------------------------------------------------------------------------

2. Isolate the x. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

x/4 = 8

First, multiply 4 to both sides

x/4(4) = 8(4)

x = 8(4)

x = 32

32 is your answer for x

--------------------------------------------------------------------------------------------------------------

hope this helps

4 0
3 years ago
Question below
Ksivusya [100]

Answer:

m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]

Therefore:

\implies 3=\dfrac{2}{3}m

\implies m=3 \times \dfrac{3}{2}

\implies m=\dfrac{9}{2}

<u>Calculate the value of H</u>

Given:

\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)

Therefore:

\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />

<u>Calculating m × H</u>

<u />

<u />\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]

\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]<u />

7 0
2 years ago
3.25- 13 tenths A:10.25 B:3.12 C:2.95
timofeeve [1]

Answer:

its B:3.12

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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