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2 years ago

Help me. please I need help

Mathematics

1 answer:

Andreas93 [3]2 years ago

3 0

I need help to please asap please help me

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What is the greatest common factor for 26rs and 30r^5s^6

LenaWriter [7]

Hello :
the greatest common factor for 26rs and 30r^5s^6 is : 2rs

4 0

2 years ago

Find the average rate of change of an exponential function f (x) over the interval 1 ≤ x ≤ 3.

Neko [114]

Answer:

Option b. 12

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

The average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

In this problem we have

$a=1$

$b=3$

$f(a)=f(1)=1$

$f(b)=f(3)=25$

Substitute

$\frac{25-1}{3-1}=12$

8 0

3 years ago

Donna paid $3 to rent shoes and then $1 for each game she played at a bowling alley. She spent a total of $8 at the bowling alle

Alexxx [7]

Answer:If shoes are for all games in row, P = 2 + 3 g If not, P = 5 g ,with g the number of games

Explanation: The price depends:if shoes are included for the whole games, you just have to pay them once and then you have to pay

g g a m e s , so P ( g ) = 2 + 3 g Else, you have to pay g s h o e s and g b o w l p a r t y ,so

P ( g ) = 2g + 3 g⇔ P ( g ) = 5 g

Hope this helped hope you get a good score on your assignment/test/quiz/homework

3 0

2 years ago

Please can anyone send a question in law of indices I really need it now

DaniilM [7]

Answer:

I think this is a pretty good question of law of indices

Step-by-step explanation:

Given that

$(9^p)(27^q)=3^n\\$

a) express n in terms of p and q ,

b) hence if p = 1 and q = 2 find the value of n

Solution to part a)

$(9^p)(27^q)=3^n\\\\$

Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,

$(3^2)^p(3^3)^q=3^n\\$

now we multiply p with 2 and

multiply q with 3 respectively,

$(3^{2p})(3^{3q})=3^n\\$

now since the bases are same and are multiplying the exponents will add themselves like this, in this equation the number 3 is the base

$3^{2p+3q}=3^n\\$

now since the bases on the left hand side and on the right hand side are equal the exponents will also be equal so now,

$2p+3q=n\\$

hence n is expressed in terms of p and q

Solution to part b)

if p = 1 and q = 2 we plug in these values in the above equation we found for n

n = 2p + 3q

n = 2(1) + 3(2)

n = 2 + 6

n = 7

6 0

2 years ago

Solve showing all work Y=x^2+3 y=x+5

Romashka-Z-Leto [24]

Answer:

x=2 , x=(-1)

Step-by-step explanation:

y=x^2+3----------1

y=x+5-------------2

1=2

x^2+3 = x+5

x^2-x-2=0

(x-2)(x+1)=0

x=2 , x=(-1)

8 0

2 years ago