Answer: the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Step-by-step explanation:
Given data;
lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min
hence, height = 1 / ( 52.0 - 50.0) = 1 / 2
now the probability that the class length is between 50.8 and 51 min = ?
P( 50.8 < X < 51 ) = base × height
= ( 51 - 50.8) × 1/2
= 0.2 × 0.5
= 0.1 ≈ 10%
therefore the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
A. Re(z)= 32 and Im(z)= 41.9
The real part of a complex number z=a+bi is ‘a’, and the imaginary part is ‘b’
First choice is "1 of 10 grape lollipops from 35 lollipops"
The probablity is 10/35 = 2/7
Second choice is "1 of 18 apple lollipops from 34 lollipops"
So probablity is 18/34 = 9/17
Between this is AND so you have to these probablities multiply:
P(A) = 2/7 * 9/17 = 18/119
P(A) = 18/119 * 100% = 1800/119 %
It is approximaly <span>15,1 %.
NOT MY ANSWER!!!
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An architect plans to make a drawing of the room of a house. The segment LM represents the ceiling of the room. He wants to construct a line passing through Q and perpendicular to side LM to represent a wall of the room. He uses a straightedge and compass to complete some steps of the construction, as shown below:
