Answer:
Solution given;
for sphere
radius [r]:12inches
another
radius [R]:9inches
Now
difference in volume of sphere:
volume of sphere of having radius [r-R]
=
-
=
(12³-9³)
= 1332π cubic inches
The volume of the larger sphere is <u>___1332</u>__π cubic inches greater than the volume of the smaller sphere.
(0.00142857)=-x is your answer
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
1.4 decameter because a decameter equals to meter divided by 10
Answer:
0.0833333333...
Step-by-step explanation:
The 3 goes on forever, just for your information.
Hope this helps!
