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Norma-Jean [14]
2 years ago
7

I need help with this ASAP I will mark brainlest. The question is in the picture below

Mathematics
2 answers:
miv72 [106K]2 years ago
7 0
The answer is and should be eight
Vilka [71]2 years ago
4 0

Answer:

8

Step-by-step explanation:

You might be interested in
Please help me asap!
Mazyrski [523]

Answer:

x value is 10 as per as the question its value is 10

3 0
3 years ago
Sam and Bethan share £54 in the ratio of 5:4 work out how much each gets
Sindrei [870]
Answer:
Sam gets £30 and Bethan gets £24.
Why?
When dealing with ratios, add up the numbers in the ratio.
5 + 4 = 9
Now, divide the total amount of money by that number.
£54/9 = 6
Now you have the base rate. Multiply each quantity in the ratio by this number.
5*6 = 30
4*6 = 24
Now, the ratio is (in euro) 30:24. This means that Sam has £30 and Bethan has £24.
Check:
30 + 24 = 54
6 0
3 years ago
A fencing company charges $22 per foot to install a wood fence. How much will it cost to install a wood fence around a rectangul
borishaifa [10]
20+20+38+38=116

116×22 = 2552

It will cost $2,552 to install the wood fence.
4 0
3 years ago
(3x-4y)^2-(3x-4y)(3x+4y)
zheka24 [161]

Answer:

-24xy + 32y^2

Step-by-step explanation:

Hello!

We can use the special binomial product formulas:

  • (a + b)^2 = a^2 + 2ab + b^2
  • (a + b)(a - b) = a^2 - b^2

<h3>Simplify</h3>
  • (3x - 4y)^2 - (3x - 4y)(3x + 4y)
  • (9x^2-24xy+16y^2) - (9x^2 - 16y^2)
  • 9x^2 - 9x^2 - 24xy + 16y^2 + 16y^2
  • -24xy + 32y^2

The simplified form is -24xy + 32y^2

6 0
1 year ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

A=P(1+r)^x

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

1000=P(1+r)^0\implies P = 1000

A = 1900 when x = 1,

1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9

Thus, the required function that represents the population after x days,

A=1900(1+0.9)^x=1900(1.9)^x

If x = 4,

The number of mosquito after 4 days,

A=1900(1.9)^4 = 24760.99\approx 24761

If A = 60,000,

60000 = 1900(1.9)^x

\frac{600}{19}=1.9^x

Taking log both sides,

\log(\frac{600}{19})=x\log 1.9

\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4

Thus, there will 60,000 mosquitoes after 5 days.

6 0
3 years ago
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