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NARA [144]
3 years ago
10

Describe the transformations for the given expressions

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

wow thats a lot let me write this down

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What is the solution to the equation 4x-6 = 10x-3?
solniwko [45]
The solution would be -1/2

4x-6=10x-3
-6=6x-3
-3=6x
X=-1/2

Hope this helps
8 0
3 years ago
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What is the mode (most frequent) of the following data set?
Klio2033 [76]

it`s definitely 2........

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3 years ago
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What set/sets of real numbers does -54/19 belong to?
ahrayia [7]

That is a rational number since you can write it as a ratio (=fraction).

7 0
4 years ago
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4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10
Andrew [12]

Given the function f(x);

f(x)=-4x^2+4x-1

Evaluating the function f(x+h);

\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}

So;

f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1

Evaluating the second function;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}

simplifying further;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}

Therefore, we have;

undefined

7 0
1 year ago
Given m||n, find the value of x. (4x-7) degrees (3x+9) degrees It's transversal problems with equations Can anyone help please
Ratling [72]

Answer:

See explanation

Step-by-step explanation:

Given

\angle 1 = 4x - 7

\angle 2 = 3x + 9

Required

Find x

The question is incomplete, as the relationship between both angles is not given

(1) If they are supplementary, then

\angle 1 + \angle 2 = 180

3x + 9 + 4x - 7 = 180

Collect like terms

3x + 4x = 180+7-9

7x = 178

Divide both sides by 7

x = 25.43

(2) If they are complementary, then

\angle 1 + \angle 2 = 90

3x + 9 + 4x - 7 = 90

Collect like terms

3x + 4x = 90+7-9

7x =88

Divide both sides by 7

x = 12.57

(3) If they are vertically opposite angles, then

\angle 1 = \angle 2

So, we have:

4x - 7 = 3x + 9

Collect like terms

4x - 3x = 9 +7

x = 16

5 0
3 years ago
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