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3 years ago

10

Describe the transformations for the given expressions

1 answer:

Vlad1618 [11]3 years ago

7 0

Answer:

wow thats a lot let me write this down

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Write the number in standard notation. 4.16 *10^-5 0.00000416 0.0000416 0.000416 –208

zalisa [80]

$4.16\cdot10^{-5}\\\\move\ the\ decimal\ 5\ place\ left\\\\4.16\cdot10^{-5}=0.0000416$

4 0

3 years ago

What is the result when 4x4 + 6x3 – 19x2 – 8x – 10 is divided by x + 3? If

-Dominant- [34]

Answer:

Step-by-step explanation:

Idk

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3 years ago

Please Help ASAP!! Marking Brainliest!! Divide <img src="https://tex.z-dn.net/?f=12x%5E2%20%2B%204x%5E3%20%2B%2018%20%2B%2016x"

MrMuchimi

Answer:

The answer is C

Step-by-step explanation:

Just calculate it

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3 years ago

What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the la

olga55 [171]

Let's say the first number is "a"
the next consecutive can just be "a+1" and the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2

now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5

thus a(a + 1) = 5(a + 2) - 5 <----- solve for "a"

7 0

3 years ago

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

$f(x) = 4x^2 - 3x + 6$

6 0

3 years ago