Answer:
a) the distance the ball moves up the ramp is approximately 9.35 meters
b) the tme required for the ball to return to the girls' hands is 6.34 seconds
Explanation:
The movement of the ball can be describe by a rectilinear movement with constant (negative) acceleration of 0.19 g = 1.862 m/s^2
Therefore the kinematic equations for the case the girl launches the ball at 5.9 m/s, we can write:
We use the second equation above to find the time it takes for the velocity to reduce to zero (and start the movement back down the ramp), and then use the time found to calculate the distance;
We use this time to find the distance the ball moves up the ramp:
so the distance the ball moves up the ramp is approximately 9.35 meters
The ball will return to the hands of the girl in the double of the time it took to reach the max distance, that is 2 times 3.17 sec = 6.34 sec
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Answer:
पत्र- अपने क्षेत्र की सड़कों की बुरी दशा की जानकारी देते हुए और उन्हें ठीक कराने की प्रार्थना करते हुए नगर निगम अधिकारी को पत्र लिखिए |
It will be unaffected by the magnet because it has no magnetic field. If you were to maybe have electricity going through it is the only way it would have anything to do with the magnet.
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We can obtain the answer easily if we assume the gas here is an ideal gas. We can use t he expression:
PV = nRT
we set nR/V = k
P/T = k
P1/T1 = P2/T2
when P2 = 3P1
P1/10 = 3P1/T2
T2 = 30 degrees Celsius