Answer:
a= - 0.79 m/s²
Explanation:
Given that
Speed ,u = 20 mi/h
We know that
1 mi/h= 0.44 m/s
Therefore ,u = 8.94 m/s
Distance ,s= 50 m
Lets take the acceleration of the car = a m/s²
The final speed of the car ,v = 0 m/s
We know that
v²= u² + 2 a s
Now by putting the values
0²= 8.94² + 2 x a x 50
a= - 0.79 m/s²
Therefore the acceleration will be - 0.79 m/s².
Answer:
Speed of 0.08 kg mass when it will reach to the bottom position is 1.94 m/s
Explanation:
When rod is released from rest then due to unbalanced torque about the hinge the system will rotate
Now moment of inertia of the system is given as
now we have
now we have
so we have
now by energy conservation we can say work done by gravity must be equal to change in kinetic energy
so we have
Now speed of 0.08 kg mass when it reaches to bottom point is given as
We will have that the diagram will be the following:
Here "F" is the force the shuttle is using to take off, friction is the friction with the air and "W" is the weight of the shuttle.
