You can pay $4.80 for 8 pounds of sugar or $11.75 for 25 pounds of

Mathematics

2 answers:

cricket20 [7]3 years ago

7 0

25 pounds would be a better deal

anzhelika [568]3 years ago

6 0

I think it is 25 pounds

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What is the value of m?

Dima020 [189]

$\huge \underline \mathcal{Answer}$

The given angles forms linear pair, and we know the angles forming linear pair are supplementary,

Therefore,

Angle MHJ + Angle MHL = 180°

Let's solve :

$(5m + 100) \degree + (2 m + 10) \degree = 180 \degree$

$7m + 110 \degree = 180 \degree$

$7m = 70 \degree$

$m = 10 \degree$

Value of variable m = 10°

$\mathrm{✌TeeNForeveR✌}$

3 0

3 years ago

A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40

bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .