Answer:
Let the number be x.
Given: 33 times a number x, subtracted from 18, is less than -90.
we can write this statement in inequality form, i.e,
![18-33x](https://tex.z-dn.net/?f=18-33x%3C-90)
Now, to find the solution set for this inequality:-
![18-33x](https://tex.z-dn.net/?f=18-33x%3C-90)
Subtraction poperty of equality states that you subtract the same number from both sides of an equation.
Subtract 18 from both sides,
Simplify:
![-33x](https://tex.z-dn.net/?f=-33x%3C-108)
Multiply both sides by -1 (reverse the inequality)
or
Divide both sides by 33, we get
![\frac{33x}{33}= \frac{108}{33}](https://tex.z-dn.net/?f=%5Cfrac%7B33x%7D%7B33%7D%3D%20%5Cfrac%7B108%7D%7B33%7D)
Simplify:
![x>\frac{36}{11}](https://tex.z-dn.net/?f=x%3E%5Cfrac%7B36%7D%7B11%7D)
Therefore, the solution set for this inequality is,
[
The solution using a fraction or integer is, tex]x>\frac{36}{11}[/tex] 0r ![x>3\frac{3}{11}](https://tex.z-dn.net/?f=x%3E3%5Cfrac%7B3%7D%7B11%7D)