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Burka [1]
2 years ago
6

Find the length of segment JK with endpoints J(4, 8) and K(-1, -2). Leave the answer as a radical. Simplify if necessary

Mathematics
1 answer:
Alex777 [14]2 years ago
6 0

Answer:

The length of segment JK is 5\sqrt{5} ⇒ C

Step-by-step explanation:

The formula of the distance between the two points (x1, y1) and (x2, y2) is

d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

Let us use the formula above to solve the question

∵ Jk is a line segment

∵ J = (4, 8) and K = (-1, -2)

∴ x1 = 4 and y1 = 8

∴ x2 = -1 and y2 = -2

→ Substitute them in the formula above

∵ JK = \sqrt{(-1-4)^{2}+(-2-8)^{2}}

∴ JK = \sqrt{(-5)^{2}+(-10)^{2}}

∴ Jk = \sqrt{25+100}

∴ Jk = \sqrt{125}

→ Simplify the root

∵ 125 = 5 × 5 × 5

∴ \sqrt{125} = 5\sqrt{5}

∴ JK = 5\sqrt{5}

∴ The length of segment JK is 5\sqrt{5}

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4 0
3 years ago
In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 4x-3 and HE = 4y + 1. Find the values of x and y. The diagram is not drawn to s
GalinKa [24]
Rule: The diagonals of any parallelogram bisect each other. In other words, they cut each other in half.

This means DF is cut into two equal pieces: DH and HF.
Similarly, GE is cut into two equal pieces: GH and HE.

DH = HF
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GH = HE
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4(x)-3 = 4y+1
4(2y-5)-3 = 4y+1 ... x has been replaced with 2y-5
8y-20-3 = 4y+1
8y-23 = 4y+1
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If y = 6, then x is
x = 2y-5
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--------------------------------------------

Answers: 
x = 7 and y = 6

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