Answer:
H2SO4 (aq) + 2LiOH (aq) --> Li2SO4 (aq) + 2H20 (l)
The answer is <span>D. Nonvascular plants. These plants are usually very short and can't grow to be very tall. A good example is moss.
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Answer:
2 Al(s) + 3 Fe²⁺(aq) → 2 Al³⁺(aq) + 3 Fe(s)
6 electrons are transferred.
Explanation:
Let's consider the following standard reduction potentials.
E°(Al³⁺/Al) = -1.66 V
E°(Fe²⁺/Fe) = -0.44 V
The one with the highest standard reduction potential will occurs as a reduction and the other will occur as an oxidation. The corresponding half-reactions are:
Oxidation: Al(s) → Al³⁺(aq) + 3 e⁻
Reduction: Fe²⁺(aq) + 2 e⁻ → Fe(s)
To get the global equation, we have to multiply both half-reactions by numbers that assure that the number of electrons gained and lost are the same, and then add them.
2 × (Al(s) → Al³⁺(aq) + 3 e⁻)
3 × (Fe²⁺(aq) + 2 e⁻ → Fe(s))
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2 Al(s) + 3 Fe²⁺(aq) + 6 e⁻ → 2 Al³⁺(aq) + 6 e⁻ + 3 Fe(s)
2 Al(s) + 3 Fe²⁺(aq) → 2 Al³⁺(aq) + 3 Fe(s)
In order to determine if compounds X and Y are the same, the mole percentages of the elements present should be equal in both compounds.
For compound X
number of moles H = 15/ 1 =15 mol H
number of moles O = 120/ 16 = 7.5 mol O
total moles = 22.5 mol
mole percentages
% mole H = 67%
% mole O = 33%
For compound Y
mole of H = 2 /1 = 2
mole of O = 32/16 = 2
total mole = 4 mole
mol %
% mol H = 50%
% mol O = 50%
there the two compounds are not the same.