A^2 + b^2 = c^2....where a and b are the legs, c is the hypotenuse
3^2 + b^2 = 7^2
9 + b^2 = 49
b^2 = 49 - 9
b^2 = 40.....take sqrt of both sides, eliminating the ^2
b = square root of 40 <==
2/3 of a pizza is more than half of the pizza.
3/6 = 1/2, so 3/6 of a pizza is exactly half of the pizza.
Given that two pizzas are of different sizes you need to calculate the areas of each pizza and compare them.
Assumming that the two pizzas are circular, you can calculate the area of each pizza from the formula of the area for a circle:
Area of a circle = π * (radius)^2.
Call r the radius of Jake's pizza and R the radius of Al's pizza. Then:
Area of Jake's pizza = π (r^2) and 2/3 of that is: 2π(r^2) / 3.
Area of Al's pizza = π (R^2) and 1/2 of that is π(R^2)/2
So, what you have to do is to use the radius of each pizza, calculate above formulaes and verify whether the results are the same or not.
Equation: 7x - 3y = 21
3y = 7x - 21
Divide both sides by 3,
y = 7/3x - 7
Compare it with principle equation, y = mx + c
Here, slope (m) = 7/3
In short, Your Answer would be: 7/3
Hope this helps!
Answer:
B.
Step-by-step explanation:
