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3 years ago

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Brent's neighbor paid him for fixing her roof. Brent shares the money equally with his brother who helped him on the job. If Bre

nt's neighbor paid him x dollars, which expression represents the amount of money Brent has after he pays his brother?

1 answer:

anygoal [31]3 years ago

4 0

X/2 because he divided the money into two equal parts and gave one part to his brother, so he only has one part of the x divided into two.
hope this helps.........

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What is d/4 equal to (evaluate expression)??????

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John took a 5 ½ mile walk to his friend’s house. He left at 11 a.m. and arrived at his friend’s house at 1 p.m. What was John’s

olganol [36]

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5.5 miles over 2 hours--> 5.5/2= 2.75 miles per hour was his average walking speed. 5.5 miles over 2.5 hours --> 5.5/2.5= 2.2 miles per hour on the return trip meaning that his average speed was (2.75-2.2= 0.55) 0.55 miles per hour lower on the return trip

Step-by-step explanation:

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3 years ago

Sin(x2 y2 da r , where r is the region in the first quadrant between the circles with center the origin and radii 1 and 5

Rudik [331]

I assume there's a plus sign missing above...

Convert to polar coordinates, using

$\begin{cases}x(r,\theta)=r\cos\theta\\y(r,\theta)=r\sin\theta\end{cases}$

Then the Jacobian is

$\dfrac{\partial(x,y)}{\partial(r,\theta)}=\begin{vmatrix}x_r&y_r\\x_\theta&y_\theta\end{vmatrix}=\begin{vmatrix}\cos\theta&\sin\theta\\r\sin\theta&-r\cos\theta\end{vmatrix}=-r$

Then

$\mathrm dA=\mathrm dx\,\mathrm dy=|-r|\,\mathrm dr\,\mathrm d\theta=r\,\mathrm dr\,\mathrm d\theta$

so the integral can be written as

$\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_1^5r\sin(r^2)\,\mathrm dr\,\mathrm d\theta$

Let $s=r^2$ , so that $\dfrac{\mathrm ds}2=r\,\mathrm dr$ .

$\displaystyle\frac12\int_0^{\pi/2}\int_1^{25}\sin s\,\mathrm ds\,\mathrm d\theta=-\frac12(\cos25-\cos1)\int_0^{\pi/2}\mathrm d\theta=\frac\pi4(\cos1-\cos25)$

3 0

3 years ago

A person is standing on a cliff that is 200ft above a body of water. The person looks down at an angle of depression of 42o at a

velikii [3]

Answer:

524.5 feet

Step-by-step explanation:

Given: Height of cliff= 200 ft

Angle of depression at sail boat is 42°

Angle of depression at yacht is 15°

Lets assume distance sailboat from the bottom of cliff is " $d_1$ "

And assume distance yacht from the bottom of cliff is " $d_2$ "

Now using tangent rule to solve it.

we know, $tan\theta = \frac{opposite}{adjacent}$

Distance sailboat from the bottom of cliff; $tan 42= \frac{200}{d_1}$

Using trignometry table to know the value of tan 42°

⇒ $0.90= \frac{200}{d_1}$

cross multiplying both side.

⇒ $d_1= \frac{200}{0.90} = 222.22 \approx 222$

∴ Distance sailboat from the bottom of cliff ( $d_1)$ = 222 feet

Distance yatch from the bottom of cliff; $tan 15= \frac{200}{d_2}$

Using trignometry table to know the value of tan 15°

⇒ $0.2679= \frac{200}{d_2}$

cross multiplying both side.

⇒ $d_2= \frac{200}{0.2679} = 746.54 \approx 746.5$

∴Distance yacht from the bottom of cliff $(d_2)$ = 746.5 feet.

Next, finding the distance between sailboat and yacht.

Distance between sailboat and yacht = $d_2-d_1$

⇒ Distance between sailboat and yacht= $746.5-222= 524.5\ ft$

∴ Distance between sailboat and yacht is 524.5 feet.

3 0

3 years ago