Answer:
Step-by-step explanation:
B = {p , q , r}
Number of subsets = 
Her, n is the number of elements in the set.
Number of subsets = 2³ = 8
Let’s assume that Laura has x$
Jose = 8+ x
Keith= 3x
So the total is equal to
118= x + 8 +x + 3x
118= 5x + 8
Subtract 8 from both sides
110= 5x
Divide 5 by both sides
22$= x which is what Laura has
Jose will have :8+22= 30$
Keith will have :3*22=66$
Answer:
Step-by-step explanation:
Change into an improper fraction. 2247/10 then divide. So, 224.7. Or since you know 7/10 is 0.7 just add 224
Answer:
3. - 8n² -8n + 3
Step-by-step explanation:
(4n^4 - 8n +4) - (8n² + 4n^4 +1)
Firstly, open the brackets.
= 4n^4 - 8n +4 - 8n² - 4n^4 - 1
Now, group like terms.
= 4n^4 - 4n^4 - 8n² -8n - 1 + 4
4n^4 - 4n^4 cancel out with each other since one is negative and the other is positive. So we're left with - 8n² -8n - 1 + 4
= - 8n² -8n - 1 + 4
= - 8n² -8n + 3
