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dexar [7]
3 years ago
10

Which image shows a rotation of quadrilateral ABCD 270° around the origin?

Mathematics
2 answers:
morpeh [17]3 years ago
6 0

Answer:

First one.

Step-by-step explanation:

Sever21 [200]3 years ago
4 0

Answer:

The first one

Step-by-step explanation:

The second one is reflection over the x axis and the third is reflection over the y axis

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Mary's dog needs medication she told the veterinarian that the dog weighs 30 pounds the medicine is measured as 16 mg for each k
shtirl [24]

Answer:

30 pounds is 13.6078 kilograms.

13 x 16 = 208.

Mary's dog should be given 208 mg of medicine.

6 0
3 years ago
Expressions  with mixed operations Evaluate.<br> 2.3+3.7-2/27.5-4*5.625
masya89 [10]
2.3+3.7-2/27.5-4*5.625. use pedmas.
=appromaxietly -16.57

5 0
3 years ago
What is the correct answer
krek1111 [17]

Answer:

3x - 9 - (6 / (x+4))

Step-by-step explanation:

               3x - 9

              |----------------------------------------

(x +4)       | (3x^2 + 3x - 42 )

                 3x^2 + 12x

           ------------------------------

                          -9x - 42

                          -9x - 36

-----------------------------------

                                 - 6

Answer: 3x - 9 - (6 / (x+4))

8 0
3 years ago
Read 2 more answers
What is the answer to this quation
svetlana [45]

Answer:

Step-by-step explanation:

g(t)=t^2 - t

f(x) = (1 + x)

g(f(x)) = f(x)^2 - f(x)

g(f(x)) = (x + 1)^2 - x - 1

g(f(0)) = (0 +1)^2 - x - 1

g(f(0)) = 1 - 1  - 1 = -1

================================

f(x) = 1 + x

f(g(t)) = 1 + g(t)

f(g(t)) = 1 + t^2 - t

f(g(0)) = 1 + 0 - 0

f(g(0)) = 1

The answer I'm getting is 0.

8 0
3 years ago
I need some help with these in kinda like a essay form
WINSTONCH [101]

A. The amount (A) at the end of t years of continuous compounding of principal P at rate r will be

... A = Pe^(rt)

For P=1000, r=.02, and t=1, The amount is

... A = $1000e^(.02·1) = $1020.20134

B. The formula for daily compounding is

... A = P(1 + r/365)^(365t)

Using the same values of P, r, t, the amount is

... A = $1000(1 +.02/365)^365 = $1020.20078

Continuous compounding produces a larger result.

The result gets larger the more often compounding occurs. Continuous compounding is the highest possible rate at which compounding can take place, so produces the largest possible result.

C. The balance at the end of the year when interest is compounded n times per year is given by

... A = P(1 + r/n)^n

Each year interest is compounded this way, the amount is multiplied by

... (1 + r/n)^n

When this happens each year for t years, the multiplier has been applied t times. Exponentiation is used to represent the effect of such repeated multiplication, so the balance at the end of t years is

... A = P((1 + r/n)^n)^t = P(1 +r/n)^(nt)

D. (Note the previous answer assumed the existence of this answer.) The same logic as for C above applies for each period that compounding takes place. That is, if compounding occurs n times per year, the interest rate applied for each period is the nominal annual rate r divided by the number of periods n. The multiplier applied to the initial principal amount is

... (1 + r/n)

When than factor is used n times during the year, the multiplier of the initial principal amount is

... (1 + r/n)·(1 + r/n)· ... ·(1 + r/n) . . . where the factor is applied n times.

In more compact notation, this multiplier is

... (1 +r/n)^n

When that multiplier is applied to principal P, the account balance A at the end of the year is ...

... A = P(1 +r/n)^n

7 0
3 years ago
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