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3 years ago

The sum of two consecutive odd integers is 316. Find the two odd integers.

1 answer:

5 0

1, 3, 5, 7, 9 ......
notice, there are consecutive odd integers, every other number
skip one, another, skip one, another and so on

so, from 1 to 3, is 1 + 2 =3
5 is 3 +2
7 is 5+2
and so on

let us pick an odd integer, hmmm say "a"
to find the next odd one, it'd be "a + 2" of course :)

we know their sum is 316
so $\bf a+(a+2)=316\impliedby \textit{solve for "a"}$

once you found "a", the next one is, well, "a + 2" :)

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Flip a coin 10 times and record the observed number of heads and tails. For example, with 10 flips one might get 6 heads and 4 t

zepelin [54]

Answer:

The greater the sample size the better is the estimation. A large sample leads to a more accurate result.

Step-by-step explanation:

Consider the table representing the number of heads and tails for all the number of tosses:

Number of tosses n (HEADS) n (TAILS) Ratio

10 3 7 3 : 7

30 14 16 7 : 8

100 60 40 3 : 2

Compute probability of heads for the tosses as follows:

n = 10 tosses

$P(\text{HEADS})=\frac{3}{10}=0.30$

The probability of heads in case of 10 tosses of a coin is -0.20 away from 50/50.

n = 30 tosses

$P(\text{HEADS})=\frac{14}{30}=0.467$

The probability of heads in case of 30 tosses of a coin is -0.033 away from 50/50.

n = 100 tosses

$P(\text{HEADS})=\frac{60}{100}=0.60$

The probability of heads in case of 100 tosses of a coin is 0.10 away from 50/50.

As it can be seen from the above explanation, that as the sample size is increasing the distance between the expected and observed proportion is decreasing.

This happens because, the greater the sample size the better is the estimation. A large sample leads to a more accurate result.

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3 years ago

In a certain game of chance, your chances of winning are 0.2. if you play the game five times and outcomes are independent, the

ikadub [295]

<span>Winning Probablity = 0.2, hence Losing Probability = 0.8 Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0) Winning once W1 is equal to L4, winning zero times is losing 5 times. p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5); p (W1) + p(W0) = p(L4) + p(L5) p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5 p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>

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3 years ago

(3x^4-x^3-4x^2-2x-20)÷(x^2+2) using long division

rosijanka [135]

Answer is below..............

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3 years ago

Please help. <br><br><br> The best answer will get brainliest.

Margaret [11]

Answer:

Mean= 10

Step-by-step explanation:

Mean= Total value of data/Number of datas given

=3+2+26+9/4

=40/4

=10

Mean= 10

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4 years ago

Given: AB = 12

Alexxx [7]

In proving that C is the midpoint of AB, we see truly that C has Symmetric property.

<h3>What is the proof about?</h3>

Note that:

AB = 12

AC = 6.

BC = AB - AC

= 12 - 6

So, AC, BC= 6

Since C is in the middle, one can say that C is the midpoint of AB.

Note that the use of segment addition property shows: AC + CB = AB = 12

Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6

Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.

See full question below

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive

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3 0

2 years ago