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snow_lady [41]
3 years ago
9

An envelope is 3 inches wide, and it measures 7 inches along the diagonal. What is the envelope’s length? If necessary, round to

the nearest tenth.
Mathematics
1 answer:
Crank3 years ago
7 0

The length of the envelope is 6.3 inches

Step-by-step explanation:

Width of the envelope = 3 inches

Diagonal of the envelope = 7 inches

To find:

The length of the envelope.

Let the length of the envelope be 'l'

We can use pythogoras theorem to calculate the length.

l = √(49-9)

l = √(40)

l = 6.3 inches

The length of the envelope is 6.3 inches

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How do u work out what fraction is equal to 1/8
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3 years ago
How do you do number 1?<br>Whenever I tried to answer it, I always get fraction. help me.​
Flura [38]

Answer:

The pairs are (13,15) and (-15,-13).

Step-by-step explanation:

If n is an odd integer, the very next odd integer will be n+2.

n+1 is even (so we aren't using this number)

The sum of the squares of (n) and (n+2) is 394.

This means

(n)^2+(n+2)^2=394

n^2+(n+2)(n+2)=394

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Combine like terms:

2n^2+4n+4=394

Subtract 394 on both sides:

2n^2+4n-390=0

Divide both sides by 2:

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n+15=0

Subtract 15 on both sides:

n=-15

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n=13

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Let's check both results

(n,n+2)=(13,15)

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(-15)^2+(-13)^2=225+169=394.  So (-15,-13) looks good!

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