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snow_lady [41]
3 years ago
9

An envelope is 3 inches wide, and it measures 7 inches along the diagonal. What is the envelope’s length? If necessary, round to

the nearest tenth.
Mathematics
1 answer:
Crank3 years ago
7 0

The length of the envelope is 6.3 inches

Step-by-step explanation:

Width of the envelope = 3 inches

Diagonal of the envelope = 7 inches

To find:

The length of the envelope.

Let the length of the envelope be 'l'

We can use pythogoras theorem to calculate the length.

l = √(49-9)

l = √(40)

l = 6.3 inches

The length of the envelope is 6.3 inches

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What is 2 5/6 + 7/4 <br> A. 2 2/5<br> B. 3 1/5<br> C. 3 4/5<br> D. 4 7/12
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Answer:

D

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Which is the same as 100 and 6 tens
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8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B28%20%7D%20%20%2B%20%20%5Csqrt%7B343%7D%20%20%5Cdiv%202%20%5Csqrt%7B63%20%7D%20"
Nadusha1986 [10]

Answer:

Step-by-step explanation:

sqrt(28): sqrt(4*7)

sqrt(4) = 2;

sqrt28)=2*sqrt(7)

sqrt(343): sqrt(7 * 7 * 7) = 7 * sqrt(7)

Note: the rule is if you have 3 equal primes under the root sign, you leave one, you throw one away, and you put one outside the root sign.

2 sqrt(63) = 2 sqrt(3*3*7)  The above rule gets modified to throw 1 three away and take the other one outside the root sign.

2sqrt(63) = 2*3 sqrt(7)

Numerator: 2*sqrt(7) + 7sqrt(7) = 9sqrt(7)

9sqrt(7)

======

6 sqrt(7)

3/2

Note without brackets I cannot be certain that I have interpreted this correctly. The division only apply to sqrt(343) / 2 sqrt(63). If this is so please leave a note.

7 0
4 years ago
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