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snow_lady [41]
3 years ago
9

An envelope is 3 inches wide, and it measures 7 inches along the diagonal. What is the envelope’s length? If necessary, round to

the nearest tenth.
Mathematics
1 answer:
Crank3 years ago
7 0

The length of the envelope is 6.3 inches

Step-by-step explanation:

Width of the envelope = 3 inches

Diagonal of the envelope = 7 inches

To find:

The length of the envelope.

Let the length of the envelope be 'l'

We can use pythogoras theorem to calculate the length.

l = √(49-9)

l = √(40)

l = 6.3 inches

The length of the envelope is 6.3 inches

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Find one solution for the equation. Assume that all angles involved are acute angles. tangent (3 Upper B minus 32 degrees )equal
raketka [301]

Answer:

Step-by-step explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan  (90 - 5B - 10 )

(3B-32 ) =  (90 - 5B - 10 )

8B = 32 + 80

B = 14° .

5 0
3 years ago
If you assume that there are exactly 365 days in a year, how many seconds are there in one year? Give your answer to the nearest
Elena L [17]

Answer:

  31,536,000

Step-by-step explanation:

There are 3600 seconds in an hour and 24 hours in a day, so ...

 (3600 s/h)(24 h/da) = 86400 s/da

Then in 365 days, there are ...

  (365 da)(86400 s/da) = 31,536,000 s

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No rounding is needed.

5 0
3 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
Hello i need the answer what is the product of 15/16
Afina-wow [57]

Answer:

The product is 240.

Step-by-step explanation:

The product is always when you multiply numbers together.

5 0
2 years ago
Read 2 more answers
Help with questions 21-23 using pemdas
taurus [48]

Answer:

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Step-by-step explanation:

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22. (11+42-5) ÷ (11-4)

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23. (17-3) × (14 - 6) -22

         14 × 8 - 22

         112 - 22

           90

5 0
3 years ago
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