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IrinaK [193]
3 years ago
15

A gym allows members to attend two free strength-building classes each month as part of their $40 monthly membership fee. If the

y want to attend additional classes during the month they must pay for each additional class they attend. The table below is shows the total amount of money the member will pay at the gym for each additional strength-building class they attend. What is the slope of the line that models this situation?
​

Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

m = 10

Step-by-step explanation:

fjfnbwdhw she djb2dh2bdub2jdb3udje <<< just for filler

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vehicle is moving with 20 m/s towards the east and another is moving with 15 m/s towards the west. If both vehicle being to more
den301095 [7]
4,200 meters
Or 4.2 km
Hope this helps good luck tho :)
5 0
3 years ago
Read 2 more answers
Marina spent $13.50 at the grocery store. She bought pears, kiwis, and pineapples. Pears cost $0.50 each, pineapples cost $1.50
kiruha [24]

Answer:

Number of pineapples = 10

Number of pears = 10 + 9 = 19

Number of kiwis = 10 - 2 = 8

Step-by-step explanation:

Money = $ 13.5

Cost of a pear = $ 0.5

Cost of a pineapple = $ 1.5

Cost of a kiwi = $ 0.3

let the number of pineapple = p  

Number of pears = p + 9

Number of kiwis = p - 2

Cost is

0.5 (p + 9) + 0.15 p + 0.3 (p - 2) = 13.5

0.5 p + 4.5 + 0.15 p + 0.3 p - 0.6 = 13.5  

0.95 p = 9.6

p = 10

So, number of pineapples = 10

Number of pears = 10 + 9 = 19

Number of kiwis = 10 - 2 = 8  

4 0
3 years ago
Read 2 more answers
Which expression is a factor of 4ab + 4a − 3b − 3?
e-lub [12.9K]
<span>4ab + 4a − 3b − 3
=4a(b + 1) - 3(b+1)
= (b+1)(4a - 3)

(b+1) and (4a - 3) are factors 

answer
</span><span>4a − 3</span>
7 0
3 years ago
For married couples living in a certain suburb, the probability that the husband willvote on a bond referendum is 0.21, the prob
jeyben [28]

Answer:

niglgapopfart

Step-by-step explanation:

12(5)6$78$???98

8 0
2 years ago
Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced
Butoxors [25]

Answer:

1) \chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

2) df = c-1 = 2-1

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

And if we replace we got:

\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

Part 2

For this case the degreed of freedom are given by:

df = c-1 = 2-1

Where c represent the number of categories c=2

And we can calculate the p value given by:

p_v = P(\chi^2_{1} >2)=0.157

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0
3 years ago
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