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Elanso [62]
2 years ago
10

Is this a proportional relationship?

Mathematics
1 answer:
seropon [69]2 years ago
8 0
Yeah

It’s is a Proportional Relationship
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What number is halfway between 0.2 and 0.3​
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Answer:

For numbers between 0.1 and 0.2, there is a 1 in the tenths' place: 0.11, 0.12, 0.13, and so on. For numbers between 0.2 and 0.3, there is a 2 in the tenths' place: 0.21, 0.22, 0.23, and so forth. For example, the number “seven and forty-two hundredths” can be written as 7.42.

Step-by-step explanation:

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What is the value of h? g = -7.1 h = 3 - 10g
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74

Step-by-step explanation:

Please separate the two functions:

g = -7.1

h = 3 - 10g

Substitute -7.1 for g in h = 3 - 10g:

h = 3 - 10(-7.1) = 71 + 3 = 74

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George works in an office as a cleaner he earns a total of $25 for five hours of cleaning later that year he earned $30 for six
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What type of triangle center is shown as point C in the figure?
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2 years ago
Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added toge
WARRIOR [948]

You can use the fact that when coefficient of x variable are of equal magnitude but opposite sign, then adding them will make the coefficient 0, thus, making the x variable eliminated.

The numbers that can be multiplied by each equation so that when the two equations are added together, the x term is eliminated is given by

Option A: –10 times the first equation and 3 times the second equation

<h3>How does elimination works?</h3>

This method is actually called method of elimination to solve a system of linear equations.

We make one specific variable's coefficients of equal magnitude so that we can subtract or add the equations and eliminate that variable to make it easy to get the value of the other variable which will then help in getting the value of the first variable (if working in dual variable system).

If we have equations:

a_1x + b_1y  = c_1\\a_2x + b_2y = c_2

then, if we want to eliminate variable x, then we have to multiply equation 1 with

- \dfrac{a_2}{a_1}

which will make coefficient of x in first equation as

a_1 \times - \dfrac{a_2}{a_1} = -a_1

Then adding both equation will eliminate the variable x.

We could've skipped that -ve sign and at then end, instead of adding, we could've subtracted the equations.

<h3>What is magnitude and sign?</h3>

5 has 5 as magnitude, and sign isn't present which means its of positive (+) sign.

-5 has 5 as magnitude and sign is negative(-).

For this case, we're multiplying both the equations but the core concept or aim is same, ie, making the coefficients of equal magnitude but with opposite sign.

<h3>Using the above facts to get the numbers to multiply the equations of the given system</h3>

The given system of equations is

\dfrac{1}{5}x + \dfrac{3}{4}y = 9\\\\\dfrac{2}{3}x - \dfrac{5}{6}y = 8

Let two numbers be p,and q who multiply equation first and second respectively to make coefficient of x of equal magnitude but opposite sign.

We have

\text{Coefficient of x in first equation}= a_1 = \dfrac{1}{5}\\\\\text{Coefficient of x in second equation} = a_2 = \dfrac{2}{3}

Multiplying with p and q will give us

p\times a_1 = \dfrac{p}{5}\\\\q \times a_2 = \dfrac{2q}{3}

We need both resultant coefficient to add up to 0, or

p/5 + 2q/3 = 0\\p = -10q/3\\q = -3p/10

Now in options, we see first equation is either getting multiplied with -10, 10, or -3,3

If we put q = 3, we get p =  -10q/3=  -10

If we put q = -3, we get p = 10

If we put q = 5, we get p = -50/3

Thus only first choice is matching the correct pairs.

Thus,

The numbers that can be multiplied by each equation so that when the two equations are added together, the x term is eliminated is given by

Option A: –10 times the first equation and 3 times the second equation

Learn more about method of elimination here:

brainly.com/question/20385690

7 0
2 years ago
Read 2 more answers
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