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belka [17]
3 years ago
12

-4x+9=2x+3

n="absmiddle" class="latex-formula">
Mathematics
1 answer:
pantera1 [17]3 years ago
3 0
X=1
(Tex)-4x+9=2x+3x(Tex)
(Te x 1)-4x1+9=2x1+3x(te x 1)
Tu=3_
2e

(T,x) = (3_ ,1)
2e
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FIRST TO ANSWER GETS BRALYIST<br> good luck :-)
Ratling [72]

Answer:

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7 0
2 years ago
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v&gt;=2i-4tj^
guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj  .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j

B )

Acceleration a is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j

Hence , this is the required solution .

5 0
3 years ago
How to solve this question. I need to show my work for this question.
IrinaK [193]

Step-by-step explanation:

Recall that 1 dozen = 12 so 4 dozen cookies has a total of 48 cookies. We are going to use the following ratios to solve the problem:

\left(\dfrac{3\:\text{eggs}}{48\:\text{cookies}}\right) and \left(\dfrac{48\:\text{cookies}}{3\:\text{eggs}}\right)

a) 12\:\text{eggs}×\left(\dfrac{48\:\text{cookies}}{3\:\text{eggs}}\right) = 192\:\text{cookies}

b) 18 dozen cookies = 216 cookies

216\:\text{cookies}×\left(\dfrac{3\:\text{eggs}}{48\:\text{cookies}}\right) = 13.5\:\text{eggs}

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Mice21 [21]
Answer B
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2 years ago
F(x) = x. What is g(x)?
Y_Kistochka [10]

Step-by-step explanation:

i think this pics will help u

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