Answer:
-15
Step-by-step explanation:
Answer:
Step-by-step explanation:
<em>Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>
<em />
<em>Height of male pilot = 74.2 inches</em>
<em />
<em>We have to find the percentile</em>
<em />
<em>X = 74.2</em>
<em />
<em>Corresponding Z score = 74.2-72.6 = 1.6</em>
<em />
<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>
<em />
<em>i.e. only 5% are below him in height.</em>
<em />
<em>Thus the malepilot is in 5th percentile.</em>
Answer:
73/5
Step-by-step explanation:
Answer:
1. vertical translation (the point goes straight up)
2. P'(0,7) (the translation was up five units and over 1 unit)
3. f(-2)=2(-2)^2-4= (all y values are 4) (0,4)
f(0)=2(0)^2-4= (all y values are -4) (0,-4)
f(1)=2(1)^2-4= (all y values are -2) (0,-2)
Answer:
C
Step-by-step explanation: