Get rid of all common factors.
36/4 = 9
x^9/x^7 = x^2
y^4/y^3 = y
36/4 = 9
x^9/x^7 = x^2
y^4/y^3 = y
A archer releases an arrow with an initial velocity of 30 feet per second at a height of 3 feet. The path the arrow takes
2 answers:
Answer:
1.97
Step-by-step explanation:
The arrow will hit the ground when the height is 0. We need to solve the quadratic equation:
Solving the quadratic equation gives two solutions −0.10 and 1.97 because we know the answer should be a positive number of seconds we can conclude that the object will hit the ground at 1.97 seconds.
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