Given:
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es = \sqrt{ \frac{p(1-p)}{n} }
where
n = the sample size.
The margin of error is
E=z^{*}E_{s}
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.
Answer: (-4,5)
Step-by-step explanation:
Rotating 90 deg. counterclockwise maps (x,y) onto (-y,x), so (5,4) maps onto (-4,5).
Answer:
x= 90-60
x=30
Step-by-step explanation:
Answer:
y = -2
Step-by-step explanation:
The horizontal line through this point has a slop of 0
