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zavuch27 [327]
2 years ago
7

Pick only 5 boxes. No LINK

Biology
1 answer:
Marianna [84]2 years ago
3 0

Answer:

nitrogen fixation, nitrification, denitrification, anammox, and ammonification

Explanation:

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Which one of the following statements is true of enzyme catalysts? A) Their catalytic activity is independent of pH. B) They are
muminat

Answer:

D) They can increase the reaction rate for a given reaction by a thousand-fold or more.

Explanation:

Enzymes are like catalysts with the only difference that they are bio-molecules. Biochemical/chemical reactions are slow because of 'transition state barriers' which require a lot of energy to overcome so enzymes rather than overcoming transition state barrier provide an alternate pathway for biochemical reactions which require comparatively less energy. Thus presence of an enzyme leads to an increase in reaction rate because alternate pathway which requires less energy makes the rate of chemical reaction rapid by a thousand-fold or more.

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3 years ago
What is an un-duplicated chromosome called?
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Unduplicated chromosomes are single chromosomes with a single line strand and one DNA molecule (if that's what you are looking for).
8 0
3 years ago
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6. Which muscles allow you to squeeze the ribs together<br> when you exhale?
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Answer:

intercostal muscles

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3 years ago
In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s
lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

<h3>A)</h3>

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp  × 1000 =

0.305  × 0.155 × 1000 = 47 individuals will be double crossover.

<h3>B)</h3>

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

<u>cc = 0.7</u>

Observed DCO / 47 = 0.7

Observed DCO = 0.7  × 47

Observed DCO ≅ 33

<h3>C)</h3>

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

<h3>D)</h3>

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0
3 years ago
Imagine a younger student did not understand the differences between the body's organs and systems. Explain the relationship in
AlladinOne [14]

Answer:

Tell the younger student that organs are singular objects and systems are a group of organs that work together to perform certain jobs.

Explanation:

Organs are singular units that play a part of human survival. (Ex. the heart cleans the blood and pushes through your veins)

Systems are a group of the singular units that work together to perform a certain function.

(Ex. Lungs, heart, veins and arteries make up the circulatory system which transports oxygen, blood, and nutrients through out your body)

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