Answer:
The answer is 0%.
Explanation:
If X⁻ represent the recessive allele that causes colorblind, and X⁺ represents the dominant allele, thus:
X⁻Y is the genotype of the colorblind man (he is carrier and he has the disease)
X⁺X⁺ is the genotype of the woman (she has normal vision and is not carrier)
When they have children together, the offspring will have the following genotypes:
X⁻Y x X⁺X⁺ = X⁻X⁺ ; X⁻X⁺ ; X⁺Y ; X⁺Y
Summarizing, they will be 50% X⁻X⁺ (women with normal vision, carrier) and 50% X⁺Y (men with normal vision, non carrier).
No child will have the disease because its expresses when the genotype is homozygous for colorblind allele (X⁻X⁻).
