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sp2606 [1]
3 years ago
6

Expand a logarithmic expression.

Mathematics
1 answer:
Korolek [52]3 years ago
4 0

we are given

log(z^3\sqrt{x^5y} )

step-1: Firstly , we will expand log terms by using property

log(a*b)=log(a)+log(b)

log(z^3)+log(\sqrt{x^5y} )

step-2: Now, we can bring exponent in front

log(a^n)=n*log(a)

=log(z^3)+log(x^5y)^{\frac{1}{2}}

=3log(z)+\frac{1}{2}log(x^5y)

step-3: we can again expand second term

=3log(z)+\frac{1}{2}(log(x^5)+log(y))

=3log(z)+\frac{1}{2}(5log(x)+log(y))

so, we will get

=3log(z)+\frac{1}{2}(5log(x)+log(y))...............Answer

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One warehouse had 185 tons of coal, another one had 237 tons. The first warehouse delivered 15 tons of coal to its clients daily
lianna [129]

Answer:

In 9 days will the second warehouse have 1.5 times more coal than the first one

Step-by-step explanation:

The coal left in warehouses after x days can be found using the equation:

  • first warehouse: 185 - 15x
  • second warehouse= 237-18x

Let the second warehouse have 1.5 times more coal than the first one after n days then  

  1. 1.5 ×(185 - 15n)=237-18n  which gives:
  2. 277,5-22,5n=237-18n and
  3. 40,5=4,5n
  4. 9=n

7 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER
saw5 [17]

The answer you want is going to be A.

Hope it helps.


3 0
3 years ago
1 tree makes approximately 230 newspapers. Estimate (by rounding each number to 1 S.F.) how many newspapers 56 trees will make.
g100num [7]

Answer:

56 trees will make 10000 newspapers.

Step-by-step explanation:

Given:

One tree makes approximately 230 newspapers.

Now, for estimating how many newspapers will be made with 56 trees.

By multiplying 56 trees with 230 newspapers we get,

56\times230=12880.

And, rounding 12880 to one significant number (1 S.F.) is 10000.

Therefore, 56 trees will make 10000 newspapers.

6 0
3 years ago
Read 2 more answers
Josefina pain rent for 5 months. She paid a total of $2045. how much did she pay per month?
djverab [1.8K]

Answer:

$409 per month

Step-by-step explanation:

If josefina paid $2045 over a time period of 5 months, then we have to divide how much she paid ($2045) by 5 to find out how much she paid for rent in 1 month.

We can use the equation: 2045 ÷ 5

When we solve that equation, we get 409 which means that josefina paid $409 per month for rent.

(sorry if this is confusing but I hope it helped)

8 0
2 years ago
The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s
Molodets [167]

Answer:

  500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

  f(x,y)=4x+2y\\g(x,y)=2x^2+y-4

The Lagrangian is ...

  \mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2

  \dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5

Since x and y are in thousands, maximum profit is to be had when the company produces ...

  500 Type A souvenirs, and 3500 Type B souvenirs

3 0
3 years ago
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