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3 years ago

For what value of h makes this equation true? (Just checking my work)

Mathematics

1 answer:

Naddik [55]3 years ago

7 0

I'm assuming that you meant h = 6 for choice B, in which case that would be correct.

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I need help with this problem down below

Misha Larkins [42]

Answer:

$y = 4$

Step-by-step explanation:

Given:

$y = \frac{7x + 1}{3x - 6}$ ,

To find the value of y, let's find x by solving 3x = 15.

3x = 15

Divide both sides by 3

x = 15/3

x = 5

Plug in the value of x into $y = \frac{7x + 1}{3x - 6}$

$y = \frac{7(5) + 1}{3(5) - 6}$

$y = \frac{35 + 1}{15 - 6}$

$y = \frac{36}{9}$

$y = 4$

8 0

2 years ago

Kate had 50 50 tickets to use for rides at the fair. She lost some of them. Her dad doubled the tickets she had left. Kate wrote

damaskus [11]

Answer: Kate expression: 2(50-t)

2 : represents twice,

50 : represents Initial number of tickets Kate has,

t : The lost tickets

50-t : represents Number of ticket Kate has After loosing t tickets

Jack expression: 100 - 2t

100 : Twice of initial ticket Kate has,

t : The lost tickets

2t : represents twice of the lost tickets,

100-2t : represents Final number of ticket Kate has.

Step-by-step explanation:

Since, According to the question,

Initially Kate has 50 tickets.

She lost tickets = t

And, after losing t ticket she has tickets = 50 - t

But, His father doubled the amount, Thus she has final tickets = 2(50-t)= 2×50 -2× t = 100 - 2t

5 0

3 years ago

Read 2 more answers

3x+4y+z=-2 2y+3z=-8 z=-3

masya89 [10]

Answer:

z=-3 so 2y+3(-3)=-8, 2y-9=-8, add 9 to both sides 2y=1 divide both sides by 2, y=1/2, so 3x+4(1/2)+-3=-2, 3x+2-3=-2, 3x-1=-2, add 1 to both sides, 3x=-1, divide both sides by 3, x=-1/3

3 0

2 years ago

Read 2 more answers

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

12c - 4 = 14c - 10 c = ? !!!

Sergio [31]

The answer to this question is c=3

3 0

3 years ago