HELPP ME PLSSS !!!!ITS IN THE PIC

Hey! i’ll give brainliest please help

Iteru [2.4K]

Answer:

A subject and a predicate

Step-by-step explanation:

Have a good day :)

7 0

2 years ago

Need some help with this question!

Veronika [31]

1. solve for x in first to just find nterms of y

x=12-y
sub that for x in other one
first divide that one by 2 to make it easier
2x-y=18
2(12-y)-y=18
24-2y-y=18
24-3y=18
minus 24 both sides
-3y=-6
divide -3
y=2

D is answer

2.
find intersection of x+y=5 and -2x+3y=6
or easiers, just test the intersections
wait, they all intersect in the same place
this is super easy
pick ANY point that is in that reigon and see if it is true

A, if we pick lets say (5,5)
that is false for x+y<5
not A

B
pick (10,0)
false for first one
not B

C
pick (0,0)
true for first
false for 2nd
not C

D. pick (-10,0)
true for first
true for 2nd

answer is D

answer is D for both questions

6 0

3 years ago

An automobile assembly line runs for 9 3/4 hours each day. employees work 3/4 hours shift. how many shifts are there in each day

babunello [35]

Answer:

the mixed fraction 9 3/4 means there are 9 4/4 s and one 3/4all togather there are 39/4 divid this by 3/4 to find the no of shifts. 39/4 ÷(3/4)

=39/4. ×4/3=13

13shifts

4 0

2 years ago

Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol

Dima020 [189]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

6 0

3 years ago

Mikel walks down 5 flights of stairs . each flight has 8 steps. which describes mikel's descent

Ludmilka [50]

Answer:

40 steps downwards

Step-by-step explanation:

4 0

2 years ago