Absolute zero is not about numbers. It's about temperature, and the
motion of molecules in gases.
You know that the temperature we feel with our skin is the result of the
average speed of all the tiny molecules zipping around or vibrating in
the solid, liquid, or gas.
The faster they're all moving, the warmer the substance feels to us.
The slower they're all moving, the cooler the substance feels to us.
When molecules slow down to zero and lose all of their kinetic energy,
that temperature is what we call 'absolute zero' ... if they're not moving
at all, then they can't move any slower.
Answer:
Explanation:
Momentum is equal to mass times velocity in kg and m/s, respectively. Therefore,
p = 100(15) so
p = 1500 ![\frac{kg*m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%2Am%7D%7Bs%7D)
The product of (wavelength) times (frequency) is always the same number ...
the speed of the wave in whatever material it's traveling through. So if the
frequency is increased, then the wavelength must <em><u>de</u></em>crease by the same
factor, in order to keep the product the same.
The problem you would encounter is measuring the height of two different people, a tall one and a short one, and getting the same answer for both of them.
No matter WHAT we're hearing out of the White House these days, you CAN'T bend and stretch your standard measuring devices, or any other 'facts', to make them fit the thing that you're measuring. This does not work. You're always entitled to your own opinions, but you're not entitled to your own facts.
When I find a problem like this, I find it helpful to think about what I know and what equation will help me.
The question tells us the frequency of the wave
![(5 \times 10^{-9})](https://tex.z-dn.net/?f=%285%20%5Ctimes%2010%5E%7B-9%7D%29)
Hz. We want to work out the wavelength. What equation links these two quantities?
Wave Speed = Frequency x Wavelength
(we know all electromagnetic waves travel at the speed of light in a vacuum)
![(3 \times 10^8) = (5 \times 10^{-9}) \times \lambda](https://tex.z-dn.net/?f=%283%20%5Ctimes%2010%5E8%29%20%3D%20%285%20%5Ctimes%2010%5E%7B-9%7D%29%20%5Ctimes%20%5Clambda)
and then divide by
![(5 \times 10^{-9})](https://tex.z-dn.net/?f=%285%20%5Ctimes%2010%5E%7B-9%7D%29)
to get the wavelength.
Wavelength =
![6 \times 10^{16}](https://tex.z-dn.net/?f=6%20%5Ctimes%2010%5E%7B16%7D)
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