2 years ago

What is the name given to the initial 150 counts in 2 minutes?

1 answer:

7 0

Divide CFU of Dilution. Divide the CFU of the dilution (the number of colonies you counted) by the result from step 4. For this example, you work out 46 ÷ 1/1000, which is the same as 46 x 1,000. The result is 46,000 CFU in the original sample.

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A 1,650 kg SUV comes uniformly to a stop. If the vehicle is accelerating at -1.3 m/s^2,

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Answer:b

Explanation:

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2 years ago

Which question cannot be answered through making measurements?

Margarita [4]

Answer: it would be A

Explanation: how are we to measure the air of a square mile

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3 years ago

You are given two objects of identical size, one made of aluminum and the other of lead. You hang each object separately from a

ollegr [7]

Answer:

Explanation:

Volume of lead object = volume of aluminium object = V

mass of lead object > mass of aluminium object

When both the objects immersed in water, the buoyant force acting on both the objects.

Buoyant force = Volume immersed x density of water x gravity

As the volume of both the objects is same, so the buoyant force acting on both the objects is same.

So, weight in air of lead object is more than the weight in air of aluminium object.

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2 years ago

An FM radio station broadcasts at 9.23 × 107 Hz. Given that the radio waves travel at 3.00 × 108 m/s, what is the wavelength of

STALIN [3.7K]

Answer:

3.2m

Explanation:

Given parameters:

Frequency of the FM radio = 9.23 x 10⁷Hz

Velocity of the waves = 3 x 10⁸m/s

Unknown:

Wavelength of the wave = ?

Solution:

To solve for the wavelength of the wave, we need the velocity equation;

Velocity = frequency x wavelength.

Radio waves are all electromagnetic radiations produced by both electrical and magnetic fields perpendicularly oriented to one another.

Since the unknown is wavelength, we solve for it:

3 x 10⁸ = 9.23 x 10⁷ x wavelength

wavelength = $\frac{ 3 x 10^{8} }{9.23 x 10^{7} }$

wavelength = 3.2m

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3 years ago

An object is 45 m above the ground when it is dropped. How fast is the object going just before it hits the ground?

leonid [27]

This is a kinematics question.
$v^{2} = v_{0} ^{2} + 2g(y - y_{0}) \\ 
v^{2} = 0 + 2(-9.8)(0 - 45) \\ 
v^{2} = 882 \\ v = \sqrt{882} = 29.7 m/s$

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3 years ago