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Brums [2.3K]
3 years ago
12

What is the name given to the initial 150 counts in 2 minutes?

Physics
1 answer:
Whitepunk [10]3 years ago
7 0

Divide CFU of Dilution. Divide the CFU of the dilution (the number of colonies you counted) by the result from step 4. For this example, you work out 46 ÷ 1/1000, which is the same as 46 x 1,000. The result is 46,000 CFU in the original sample.

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You will begin with a relatively standard calculation.Consider a concave spherical mirror with a radius of curvature equal to 60
Strike441 [17]

a) 30.0 cm

For any mirror, the radius of curvature is twice the focal length:

r = 2f

where

r is the radius of curvature

f is the focal length

For the mirror in this problem, we have

r = 60.0 cm is the radius of curvature

Therefore, solving the equation above for f, we find its focal length:

f=\frac{r}{2}=\frac{60.0 cm}{2}=30.0 cm

b) 90 cm

The mirror equation is:

\frac{1}{s'}=\frac{1}{f}-\frac{1}{s}

where

s' is the distance of the image from the mirror

f is the focal length

s is the distance of the object from the mirror

For the situation in the problem, we have

f = +30.0 cm is the focal length (positive for a concave mirror)

s = 45.0 cm is the object distance from the mirror

Solving the formula for s', we find

\frac{1}{s'}=\frac{1}{30.0 cm}-\frac{1}{45.0 cm}=0.011 cm^{-1}

s'=\frac{1}{0.011 cm^{-1}}=90 cm

c) -2

The magnification of the mirror is given by

M=-\frac{s'}{s}

where in this problem we have

s' = 90 cm is the image distance

s = 45.0 cm is the object distance

Solving the equation, we find:

M=-\frac{90 cm}{45 cm}=-2

So, the magnification is -2.

d) -12.0 cm

The magnification can also be rewritten as

M=\frac{y'}{y}

where

y' is the height of the image

y is the heigth of the object

In this problem, we know

y = 6.0 cm is the height of the object

M = -2 is the magnification

Solving the equation for y', we find

y'=My=(-2)(6.0 cm)=-12.0 cm

and the negative sign means that the image is inverted.

Part e and f are exactly identical as part b) and c).

6 0
4 years ago
What would be the acceleration in a bus moving with uniform velocity and why​
jeka57 [31]

Answer:

Then its acceleration is zero.

Explanation:

Velocity → Uniform → Constant

→ Change in Velocity = 0

A= \frac{v-m}{e} = (v=m)

a=0

3 0
3 years ago
Summarize Newton’s First Law
Tamiku [17]
Newton's first law is "An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force."

Basically it means an object won't move unless something moves it, and an object won't stop moving unless something stops it.
8 0
3 years ago
Match each measurement tool with what it measures.
Law Incorporation [45]
Thermometer-temperature
Wind vane -wind direction
Anemometer- both wind speed (and direction)
Hygrometer- humidity
5 0
3 years ago
The most common isotope of hydrogen contains a proton and an electron 'separated by about -11-27 5.0 x 10 m. The mass of proton
Brrunno [24]

Answer:

A)   F_g = 4.05 10⁻⁴⁷ N, B)   F_e = 9.2 10⁻⁸N, C)    \frac{F_e}{F_g} = 2.3 10³⁹

Explanation:

A) It is asked to find the force of attraction due to the masses of the particles

Let's use the law of universal attraction

            F = G \frac{m_1m_2}{r^2}

let's calculate

            F = 6.67 \ 10^{-11} \ \frac{9.1 \ 10^{-31} \ 1.67 \ 10 ^{-27} }{(5 \ 10^{-11})^2 }

            F_g = 4.05 10⁻⁴⁷ N

B) in this part it is asked to calculate the electric force

Let's use Coulomb's law

            F = k \  \frac{q_1q_2}{r^2}

let's calculate

            F = 9 \ 10^9 \  \frac{(1.6 \ 10^{-19} )^2}{(5 \ 10^{-11})^2}

             F_e = 9.2 10⁻⁸N

C) It is asked to find the relationship between these forces

        \frac{F_e}{F_g} = \frac{9.2 \ 10^{-8} }{4.05 \ 10^{-47} }

        = 2.3 10³⁹

therefore the electric force is much greater than the gravitational force

4 0
3 years ago
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