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2 years ago

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Carlos deposits $400 into an account that pays simple interest at a rate of 6% per year. How much interest will he be paid in th

e first 6 years?

1 answer:

kobusy [5.1K]2 years ago

5 0

Answer:

hbjnmui,lhyjngrfdxw

Step-by-step explanation:

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Subtract 2xy-8 from 5x^2+3xy+12

JulijaS [17]

Answer:

5x^2 + xy + 20

Step-by-step explanation:

Begin with 5x^2+3xy+12, Subtracting 2xy yields 5x^2 + xy + 12. Next, subtracting -8 yields 5x^2 + xy + 12 - (-8), or 5x^2 + xy + 20

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2 years ago

Sarah had 16 stickers. Al gave her 25 more. How many stickers does Sarah have now?

Amiraneli [1.4K]

Answer:

Sarah had 16 stickers. Al gave her 25 more. How many stickers does Sarah have now? 41

Step-by-step explanation:

8 0

2 years ago

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b&b inc. has ordered machine parts and receives a charge of $15 for shipping and handling plus $20 per part. write an equati

larisa [96]

Answer:

C = 15 + 20*p

Step-by-step explanation:

Cost for ordering = shipping and handling plus cost per part * number of parts

C = 15 + 20*p

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2 years ago

Can someone plz help I do not know what I am doing

PolarNik [594]

the answer is D-n is greater then or equal to nine.

because the red dot starts on nine and goes up its greater than nine and because its on nine its also going to equal it. I had a problem getting the signs messed up when I learned it but I remember the sign always eats the greater number. I hope this answer could help and I'm sorry if the answer is incorrect.

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3 years ago

#Quality answer needed <br>#No spam _/|\_

Rina8888 [55]

Answer:

<h2><em><u>5.71</u></em><em><u>%</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

Cost price of the car when Arjun bought = ₹ 3,50,000

Cost price of that same car after 1 year = ₹ 3,70,000

<em><u>So</u></em><em><u>,</u></em>

Amount of money increased on the car's price

= ₹ (3,70,000 - 3,50,000)

= ₹ 20,000

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>

Percentage of increase on the car's price

$= \frac{20000}{350000} \times 100$

<em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

$= \frac{2}{35} \times 100$

<em>[</em><em>On</em><em> </em><em>further</em><em> </em><em>Simplification</em><em>]</em>

= 5.7142......

= 5.71 (approx.)

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>Percentage</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>increase</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>car's</u></em><em><u> </u></em><em><u>price</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>5.71</u></em><em><u>%</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

7 0

2 years ago

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