-7x<-93+86
-7x<-7
x>1 is the answer
DO YOU NEED TO GRAPH TOO?
Answer:
Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).
As, DO is Dilation of Δ ABC by Scale factor of
.
Vertices of A' B'C' are

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.
The two triangles will be congruent.
AO is Dilated by a factor of half , so A'O' will be half of AO.
So, correct Statements are
1. AB is parallel to A'B'.
2.DO,1/2(x, y) =
The distance from A' to the origin is half the distance from A to the origin.
Answer:
=-3/8-7/16
Step-by-step explanation:
If b=-3/8
y=-4/7
Then b+1/4y= - 3/8 +1/4*(-4/7)= - 3/8 +1/(-16/7) =
=-3/8-7/16
Please Brainlist me
Answer:
see the prove below
Step-by-step explanation:
<u>We have to prove that </u><u>MOC=(AOM+BOM)/2</u>
Let Angle AOM=x and AOC=y . => AOB=2y ( because OC is the bisector of AOB)
So MOC= AOM+AOC=x+y
BOM=AOB+AOM=2y +x
AOM+BOM= x+2y+x=2y+2x
(AOM+BOM)/2= (2y+2x)/2=x+y=MOC
The statement is proved