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bonufazy [111]
3 years ago
7

Connor works in a department store selling clothing. He makes a guaranteed salary of $300 per week, but is paid a commision on t

op of his base salary equal to 5% of his total sales for the week. How much would Connor make in a week in which he made $2175 in sales? How much would Connor make in a week if he made xx dollars in sales?
Mathematics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

If Connor makes x dollars in sales, he will make 0.05x + 300 that week.

He makes $408.75 in a week if he makes $2175 in sales.

Step-by-step explanation:

y = 0.05x + 300

y = 0.05(2175) + 300

y = 408.75

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Step-by-step explanation:

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3 0
3 years ago
Find the solution of -x+5y=-18 5x-9y=10
noname [10]
<span>-x + 5y= -18 so x = 5y + 18
5x-9y=10
substitute </span>x = 5y + 18 into 5x - 9y = 10

5x - 9y = 10
5(5y + 18) - 9y = 10
25y + 90 - 9y = 10
16y = - 80
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x = 5y + 18
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answer
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What is the length of BC
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Where the question ??
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3 years ago
Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
Arada [10]

Answer:

a) 0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

b) n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

c) n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

\hat p=\frac{823}{1000}=0.823

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

Part c

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
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mamaluj [8]

Answer:

K=27

Step-by-step explanation:

the answer is 27

6 0
3 years ago
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