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3 years ago

7k + 5 – 2 = 7k + 3 0 Anyone sorry for so many i just need help

Mathematics

1 answer:

mamaluj [8]3 years ago

6 0

Answer:

K=27

Step-by-step explanation:

the answer is 27

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Evaluate 33/5 - 1/10

azamat

Answer:

$\large\boxed{\dfrac{13}{2}=6\dfrac{1}{2}=6.5}$

Step-by-step explanation:

We have the different denominators.

The common denominator is 10.

$\dfrac{33}{5}=\dfrac{33\cdot2}{5\cdot2}=\dfrac{66}{10}$

We can subtract these fractions now.

$\dfrac{33}{5}-\dfrac{1}{10}=\dfrac{66}{10}-\dfrac{1}{10}=\dfrac{66-1}{10}=\dfrac{65:5}{10:5}=\dfrac{13}{2}\\\\\dfrac{13}{2}=\dfrac{12+1}{2}=6\dfrac{1}{2}$

3 0

4 years ago

Read 2 more answers

Please help with these questions!!!

klasskru [66]

Answer:

Step-by-step explanation:

Q1: (x-1) * (x+1) * (x-2) * (x+2)

Q2: x'1 = -1/3, x'2 =2

Q3: i dont get this one sry

4 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

4 years ago

I NEED HELP ASAP!!!!!

lara31 [8.8K]

Answer:

W = 2.5d + 62

Step-by-step explanation:

The calf weighed 62 pounds when they were born. This gives us a base of 62 pounds - the calf cannot weigh less than 62 pounds and it does on day 0. On each day , the calf gains 2.5 pounds. We can times the number to days by 2.5 to get the gain from day 0. We can add these two values together to get the total current weight of the calf.

3 0

3 years ago

Another question I'm stuck on

qwelly [4]

M=(y2-y1)/(x2-x1) m=(-4-4)/(3-1) m=-8/2 m=-4 so the answer should be first one

7 0

3 years ago