Answer:
Step-by-step explanation:
i think the answer is B
Answer:
∠1 is 33°
∠2 is 57°
∠3 is 57°
∠4 is 33°
Step-by-step explanation:
First off, we already know that ∠2 is 57° because of alternate interior angles.
Second, it's important to know that rhombus' diagonals bisect each other; meaning they form 90° angles in the intersection. Another cool thing is that the diagonals bisect the existing angles in the rhombus. Therefore, 57° is just half of something.
Then, you basically just do some other pain-in-the-butt things after.
Since that ∠2 is just the bisected half from one existing angle, that means that ∠3 is just the other half; meaning that ∠3 is 57°, as well.
Next is to just find the missing angle ∠1. Since we already know ∠3 is 57°, we can just add that to the 90° that the diagonals formed at the intersection.
57° + 90° = 147°
180° - 147° = 33°
∠1 is 33°
Finally, since that ∠4 is just an alternate interior angle of ∠1, ∠4 is 33°, too.
The measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28
<h3>How to determine the
measure of
angle EBF?</h3>
The angle measures are given as
If m ∠ A B F = ( 8 w − 6 ) ° m ∠ A B E = [ 2 ( w + 11 ) ] ° m ∠ E B F
Rewrite the angle measures properly.
This is done, as follows
m∠ABF = (8w − 6)°
m∠ABE = [2(w + 11)]
The measure of angle m∠EBF is calculated as:
m∠ABF = m∠ABE + m∠EBF
Substitute the known values in the above equation
8w - 6 = 2(2w + 11) + m∠EBF
Open the brackets
8w - 6 = 4w + 22 + m∠EBF
Evaluate the like terms
m∠EBF = 4w - 28
Hence, the measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28
Read more about angles at
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The least common multiple of each pair of the polynomial (5y² - 80) and
(y + 4) is equal to 5(y-4)(y+4).
As given in the question,
Given pair of the polynomial is (5y² - 80) and (y + 4)
Simplify the given polynomial using (a² -b²) = (a-b)(a +b)
(5y² - 80) = 5(y² -16)
⇒(5y² - 80) = 5(y² - 4²)
⇒(5y² - 80) = 5(y -4)(y + 4)
And (y + 4) = (1) (y+4)
Least common multiple = 5(y-4)(y+ 4)
Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).
Learn more about least common multiple here
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For this case we have the following data:
So that the figure can be a rectangle, its diagonals must be equal, that is, 
In this way we have:
Clearing x we have:
Thus, x must be equal to 10 so that the figure is a rectangle.
Answer:
Option A
