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daser333 [38]
3 years ago
14

Which of the following describes the end behavior of f(x) = (1/2)^x

Mathematics
1 answer:
NARA [144]3 years ago
4 0

Answer:

as x approaches infinity, f(x) approaches 0

as x approaches -infinity, f(x) approaches infinity

Step-by-step explanation:

we can observe that 1/2 < 1 and since it's being exponentiated, the f(x) gets smaller and smaller as x gets bigger.

For example, f(0) = 1, f(1) = 1/2, f(2) = 1/4

so, as x approaches an infinitely large number, f(x) gets closer and closer to zero.

this is the opposite as x approaches a negatively large number. following exponential rules, 1/2^(x) = 2^x for all x < 0. therefore as x approaches negative infinity, f(x) approaches infinity.

in this case, f(-1) = 2, f(2) = 4, f(3) = 8

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\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

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<h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>

<em>by a random romanian guy</em>

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