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daser333 [38]
3 years ago
14

Which of the following describes the end behavior of f(x) = (1/2)^x

Mathematics
1 answer:
NARA [144]3 years ago
4 0

Answer:

as x approaches infinity, f(x) approaches 0

as x approaches -infinity, f(x) approaches infinity

Step-by-step explanation:

we can observe that 1/2 < 1 and since it's being exponentiated, the f(x) gets smaller and smaller as x gets bigger.

For example, f(0) = 1, f(1) = 1/2, f(2) = 1/4

so, as x approaches an infinitely large number, f(x) gets closer and closer to zero.

this is the opposite as x approaches a negatively large number. following exponential rules, 1/2^(x) = 2^x for all x < 0. therefore as x approaches negative infinity, f(x) approaches infinity.

in this case, f(-1) = 2, f(2) = 4, f(3) = 8

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Sunny_sXe [5.5K]

Answer:

x=-7

Step-by-step explanation:

7x2-x=7

7x2=14.

14-x=7

When you finished the last step, you will subtract 14 to both sides.

14-x=7

14-14-x=7-14

this will cancel out the 14 on the left.

And will leave you with:

-x=7-14

7-14 is -7.

and this will get you to

-x=-7

To finish this off, you have to turn the negative x/variable, into a positive x/variable.

So, you will divide both sides of the equation by the same term.

-x = -7

into

\frac{-x}{1} =\frac{-7}{1}

and it will be -7.

I hope this helps      :)

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