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Gwar [14]
3 years ago
8

Find an equation for the line thatis tangent to the curve y=5x^3-5x at the point (1,0)

Mathematics
1 answer:
lukranit [14]3 years ago
4 0
Hello,

The gradient of a tangent can be found by differentiating the equation:
\frac{d}{dx}(5x^3-5x) = 15x^2-5

Subbing in the x value of 1, the gradient therefore is 15-5 = 10, giving us m in our general equation for a line y=mx+c, i.e. y = 10x + c

We know at x=1, y is 0. Subbing this in:
0 = 10 + c, and solving for c = -10

Therefore, the equation of the tangential line at (1,0) is y=10x-10.

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Let \mu denotes the average concentration of radon gas.

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As per given , the appropriate hypothesis to test :

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Sample size : 36

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t_{df, \alpha}=t_{35,0.005}=1.690      [Using the students' t-distribution table ]

Hence, At a 5% significance level, the critical value is t_{df, \alpha}=1.690.

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