suppose a population of 200 crickets double in size every 4 months. How many crickets will there be after 2 years?

1 answer:

4 0

Well 2 years is 24 months. 24 divided by 4 is 6. 200 multiplied by 6 would equal 1200.

The total population of crickets after two years would be 1200.

You might be interested in

sam goes to the market to buy a hamburger for cookout. he buys 3 3/4 pounds if a hamburger. how many 1/4 pound patties can he ma

Alexandra [31]

3 3/4÷ 1/4
15/4÷1/4
15/4÷4/1
15*4=60
4*1=4
60/4=15
15 times 1/4 can fit into 3 3/4.

7 0

3 years ago

Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what should the in

Brrunno [24]

Distance traveled should be on y axis
hours should be on x axis
increments should be 5

8 0

3 years ago

Read 2 more answers

F(0)=1(0+3)squared + 1<br><br> Find f of zero.<br><br> What does this point represent?

zzz [600]

Answer:

Step-by-step explanation:

F(0) = 3^2+1=9+1=10

6 0

3 years ago

The amount of milk that the bakery was a 75% decrease compared to last month. (it doesn’t show a last month)

Thepotemich [5.8K]

Did you do the math homework for math homework homework for math

3 0

3 years ago

A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li

svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

15 drivers are randomly selected, so $n = 15$ .

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year. This means that $\pi = 0.08$ .

What is the probability of getting 3 or more who were involved in a car accident last year?

This is $P(X \geq 3)$ .

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

$P(X < 3) + P(X \geq 3) = 1$