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3 years ago

Which expression is equivalent to y 2

Mathematics

1 answer:

kolezko [41]3 years ago

3 0

Answer:

Hello!

Distributive property: a(b+c)=ab+ac

Minus and plus sign.

Then multiply by the numbers.

Hope this helps!

Thanks!

Have a great day!

Step-by-step explanation:

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What is 6/8 written in simplest form

gogolik [260]

It is 3/4. Hoped this helped. ~Bob Ross

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A car care company sells 45-in. Upholstery fabric for car restoration. Art bought 9 7/12 yd and 11 13/16 yd for two car projects

kvv77 [185]

Answer:

$21\frac{19}{48}\ yards$

Step-by-step explanation:

Art bought $9\frac{7}{12}$ and $11\frac{13}{16}$ yards of fabric.

Total fabric bought: $9\frac{7}{12} + 11\frac{13}{16}$

To add both fractions, we convert them into improper fractions (multiply denominator with whole number, then add the numerator) and then we find the LCM of the two denominators: 12 and 16

LCM of 12 and 16 = 48

$\frac{115}{12} + \frac{189}{16}\\\\\frac{460}{48} + \frac{567}{48}\\\\\frac{460 + 567}{48}\\\\\frac{1027}{48}$

We reduce this fraction to mixed fraction (or reduce if possible), since 1027 and 48 have no common factors.

= $21\frac{19}{48}$ yards

6 0

3 years ago

Please help with E!!

Andrej [43]

Answer:

x=15.6

Step-by-step explanation:

180-109=71

71+7=78

78/5=15.6

8 0

3 years ago

Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

<em>The correct option is C.</em>

Step-by-step explanation:

<u>Root Of Complex Numbers</u>

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

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3 years ago

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