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Fiesta28 [93]
2 years ago
14

The circumference of a circle is 40π. Find the diameter.

Mathematics
1 answer:
klasskru [66]2 years ago
8 0
D≈12.73 hope this helps
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Step-by-step explanation:

I can’t see the triangle but I can tell that’s the answer

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An athletic coach conducted an experiment to test whether a four-week stretching and flexibility program reduces the number of m
son4ous [18]

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3/2 x - 5/4 y =15 rate of change​
Alenkinab [10]

Answer:

6/5

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m is your rate of change you need to get y by itself.

3/2x - 15 = 5/4y

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3 years ago
Reduce the fraction to lowest terms m^2/m^2-n^2
Softa [21]

Answer:

\boxed{\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}}

Step-by-step explanation:

Factor \bold{m^2-n^2}

\bold{\left(m+n\right)\left(m-n\right)}

Rewrite Equation

\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}

4 0
3 years ago
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A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
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Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
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0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
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Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
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Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
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3 years ago
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