Answer:
We have 3 students and 3 positions.
Angie (A), Bradley (B) and Carnell (C)
The total number of combinations can be calculated as:
For the president option we have 3 options:
For the vice president, we have 2 options because we already took one of the students for the president's place.
For the treasurer, we only have one option, so the number of combinations is:
3*2*1 = 6 we have 6 possible combinations; those are:
![\left[\begin{array}{ccc}pres&vice&treas\\A&B&C\\A&C&B\\B&A&C\\B&C&A\\C&A&B\\C&B&A\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dpres%26vice%26treas%5C%5CA%26B%26C%5C%5CA%26C%26B%5C%5CB%26A%26C%5C%5CB%26C%26A%5C%5CC%26A%26B%5C%5CC%26B%26A%5Cend%7Barray%7D%5Cright%5D)