The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
Let the speed of one bicyclist=x mph
Let the speed of the other bicyclist=(x+3) mph
Hence:
Speed of one bicyclist:
3x+3(x+3)+2=98
3x+3x+9+2=98
6x=87
Divide both side by 6x
x=87/6
x=14.5 mph
Speed of the other bicyclist:
x+3 mph
14.5 mph+3 mph
=17.5 mph
Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
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Answer:
The reason why this may be happening is because the expenses may be higher than the amount of revenue that the business is making, the cost of rent, paying the employees and running the business may be higher than the revenue that is being made. The inflows may be higher than the outflows, in which case the profit is lower than the loss and may be the reason why the owner is having trouble keeping the business running.
The two bars ( | | ) symbolize absolute value
Absolute value is essentially just making the number given positive.
If the given number is already positive then the absolute value is the same as the original number
|-13| is 13
The absolute value of -13 is 13
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
Step-by-step explanation:
If 5! is equal to 5 × 4 × 3 × 2 × 1 and 6! is equal to 6 × 5 × 4 × 3 × 2 × 1, then 4! is equal to 4 × 3 × 2 × 1. Thus, 4! = 4 × 3 × 2 × 1, which can simplify to 24. 4! = 24.
is basically 4 × 4 × 4 × 4, which can simplify to 256.
So, 
= 
. can simplify to . Therefore, = .
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
