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3 years ago

Percents

Mathematics

2 answers:

vredina [299]3 years ago

8 0

Answer:

Step-by-step explanation:

55$ x 40% (rewritten) 55 x .4 = 22

since its 40% OFF you take 55 - 22 = 33

Then take the 33$ x 6% (rewritten)

33 x .06 = 1.98

Then take 33 and add the 6% sales tax

33 + 1.98 = 34.98

Klio2033 [76]3 years ago

3 0

It should be A if i am correct

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An empty shipping box box weighs 250 grams. The box is filled with T shirts weighs 132.5 grams. The equation W=250+132.5T repres

garik1379 [7]

Answer:

the solution means you can solve for either of the variables when one of the variables is known

Step-by-step explanation:

Given:

W=250+132.5T

Where,

W = weights in grams of the filled box

T = number of shirts in the box

T=8 when W=1310

W=250+132.5T

Substitute T = 8 into the equation

W = 250 + 132.5(8)

= 250 + 1,060

= 1,310

The solution means when number of shirts in the box is 8, the total weight in grams of the filled box is 1,310

It also means you can solve for the number of shirts if weight of the box is given as 1310

W=250+132.5T

1310 = 250 + 132.5T

1310-250 = 132.5T

1,060 = 132.5T

T = 1,060 / 132.5

= 8

T = 8

Therefore, the solution means you can solve for either of the variables when one of the variables is known

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3 years ago

This is a question in statistics. Please answer with an explanation, thanks!

Liula [17]

Answer:

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Step-by-step explanation:

ewxd

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4 years ago

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blondinia [14]

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3 years ago

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Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15

ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

$a_{n+1} = ra_{n}$

In which r is the common ratio.

This can be expanded for the nth term in the following way:

$a_{n} = a_{1}r^{n-1}$

In which $a_{1}$ is the first term.

Or even:

$a_{n} = a_{m}r^{n-m}$

The sum of the first n terms of a geometric sequence is given by:

$S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}$

Finding the common ratio:

$a_{3} = 3.645, a_{8} = 15$

$a_{n} = a_{m}r^{n-m}$

$a_{8} = a_{3}r^{8-3}$

$a_{3}r^{5} = a_{8}$

$3.645r^{5} = 15$

$r^{5} = \frac{15}{3.645}$

$r = \sqrt[5]{\frac{15}{3.645}}$

$r = 1.327$

Finding the first term:

$a_{3} = a_{1}r^{2}$

$a_{1} = \frac{a_{3}}{r^{2}}$

$a_{1} = \frac{3.645}{(1.327)^{2}}$

$a_{1} = 2.07$

Sum of the first nine terms:

$S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44$

The sum of the first nine terms of the sequence is 74.44.

8 0

3 years ago

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